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Top Forums Shell Programming and Scripting extract certain parts from a file Post 302565085 by agama on Sunday 16th of October 2011 10:44:27 PM
Old 10-16-2011
As long as you want everything after the first timestamp of 22:00 or later, then this should work:

Code:
awk ' snarf || $2+0 >= 22 { snarf = 1; print; }' log-file-name

It does require that a timestamp between 22:00 and 23:59:59 be present.
 

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AUPARSE_GET_TIMESTAMP(3)					  Linux Audit API					  AUPARSE_GET_TIMESTAMP(3)

NAME
auparse_get_timestamp - access timestamp of the event SYNOPSIS
#include <auparse.h> const au_event_t *auparse_get_timestamp(auparse_state_t *au); DESCRIPTION
auparse_get_timestamp provides an accessor function for the event's timestamp data structure. The data structure is as follows: typedef struct { time_t sec; // Event seconds unsigned int milli; // millisecond of the timestamp unsigned long serial; // Serial number of the event const char *host; // Machine's node name } au_event_t; RETURN VALUE
Returns NULL if an error occurs; otherwise, a valid pointer to the data. SEE ALSO
auparse_get_time(3), auparse_get_milli(3), auparse_get_serial(3), auparse_get_node(3), auparse_timestamp_compare(3). AUTHOR
Steve Grubb Red Hat Sept 2007 AUPARSE_GET_TIMESTAMP(3)
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