Hi there,
I was trying to add a line of text in the middle line of a file.
I have counted the lines in the file, and then I divide it into 2, after that I am stuck on how am I suppose to append the line on that file? When I tried to use this command 'second line >> filename' it appends it at... (3 Replies)
Hi all,
I have set up a simple awk script to calculate the average of values that are printed out a number of times per second (the number of time the printing occurs varies). The data is of the format shown below:
1 4.43
1 3.65
1 2.45
2 7.65
2 8.23
2 5.65
3 4.65
3 6.21
.. ..
120... (4 Replies)
Hi
New to shell script and awk and need assistance on this problem. I need to use a variable to substitute a string in an external file and write the changed info to another file.
At first I did not know if you could use a variable as the sub value but the following showed me that I can.
... (3 Replies)
Hi, I have a very simple script like below:
for n in 10 20 30
do
for a in 30 40 50 60 70 80
do
for r in 2 3 4 5 6 7
do
m=$((r*a))
count=1
while
do
echo "a = " $a ", m = " $m ", n = " $n
... (2 Replies)
Hello;
I need to print two previous lines after searching for a reg exp:
awk '/haywood/'
should produce the following
===================
p9J46THe020804 89922 Tue Oct 18 21:06 MAILER-DAEMON
(host map: lookup (haywood.com): deferred)
... (1 Reply)
Hi there, Im sure there is a simple explanation for this but I have a file like this with no balnk lines
peter
paul
john
I run the command
# var=`grep paul file.txt`
# echo $var
paul
# echo $var | wc -l
1
but when I grep for a value that isnt in the file, i still... (4 Replies)
Hello;
we have :
awk '/reg_exp/,0/
prints every line after the first occurrence of "reg_exp"
But if I want to print rest of the lines AFTER the last occurrence of "reg_exp",
how would I do it ??
Tried :
awk ' ! (/reg_exp/,0)'
But it errored...
Thank you for any... (5 Replies)
Discussion started by: delphys
5 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)