Hi,
I'd like to grep a variable that I saved in the program.
Like
grep '0\$variable1' file1
Does someone know what's wrong with this command?
Thanks a lot! (2 Replies)
Hi, I can't get this script to work (returns 0, should return 3):
$ cat A.lst | \
while read LINE
do
echo "$LINE"
grep -c "$LINE" B.tmp
done> > > > >
Socket
0
$
but in contrast this one works fine (returns 3 as expected):
$ LINE=Socket
$ grep -c $LINE B.tmp
3
$ (5 Replies)
Hi all,
I am trying to do a simple thing in my mind. However I am fairly new to bash. What I need to do is create a folder for each partition on each CD, and each partition has a unique name (with spaces in it, do not ask why, it is already done :confused: ) . All CD's will show up... (2 Replies)
can i grep a variable
say i have a variable var=`hostname` and I want to make an if statement like
if grep "esp-ueh" $var;then......
how can i do this
I dont want to store this variable in a file and the grep it because my script will be used at the same time on multiple stations and then that... (9 Replies)
how can I use grep with a variable to find a value?
cat data.out
Hello World
grep "Hello World" data.out
Hello World ## Value found
I want to do something like this but can't seem to get it to work any
suggestions would be appreciated.
var="Hello World"
grep $var data.out (3 Replies)
I have a pattern like:
column "5" is missing
PS: the no is in double quotes.
The number usally changes, so we use a loop to grep.
grep 'column "$number" is missing' filename.txt
But it is not working....
How to solve this? (2 Replies)
Hello,
I usually search extensively and have to date found what I've needed. However, this one's got me stumped. I need to create a variable as follow. The issue however is that upon execution, it freezes. $var1 isn't always present in usage.log and this is fine but I'd like it to continue with... (6 Replies)
I've got a file that I'm trying to grep through that looks like this:
alpha1
alpha2
alpha3
beta1
beta2
gamma5
gamma6
gamma7
gamma8
gamma9
and I want the output to only contain the line with the highest value for each, so the output I want is:
alpha3
beta2
gamma9
I also need... (11 Replies)
Hi,
I am trying to grep one variable over the other variable
Example:
i=abc
j=ab
grep $j $i
I am getting this error:
The error is due to $i being variable and not file. I know I could do it by putting the value of abc in a file
and then greping it. (1 Reply)
hi
i have a file which contains some messages counters.
below is the snippet on the file.
17-05-29::22:36:21|message|231
17-05-29::22:36:31|message|222
17-05-29::22:36:41|message|213
17-05-30::22:36:51|message|221
17-05-30::22:37:01|message|227
17-05-30::22:37:11|message|207... (5 Replies)
Discussion started by: scriptor
5 Replies
LEARN ABOUT V7
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)
10-13-2011
