10-10-2011
Quote:
Originally Posted by
COKEDUDE
I wanna do it the complicated way
.
Without xargs please
. I wanna do it the complicated way
.
The most complicated way is try and discover yourself. Isn't it?
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1. UNIX for Dummies Questions & Answers
i would like to pass a variable to awk wherein the variable comes from external loop.
i tried this...
let x=0
until test $x -eq 32
do
cat file | awk '{ print $1 , "Number" , $($x) }' >> output
done
thanks, (4 Replies)
Discussion started by: inquirer
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I am trying to pass 2 shell variable's ("START" and "END") define earlier in the script to this awk statement, but i can't seem to pass it on. PLs help.
set START = xxxx
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I have an awk statement where I Need to pass an environment variable but I cannot get it to work:
My evironment varible examples below:
$FILE1=/dev/fs/file.new
$FILE2=/dev/fs/file.old
Code below:
awk -F"|" '
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{ arr=1 }
}
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HI all,
some more mistery about AWK, I hope you can help me out:
1)
I have a normal ksh script and sometime I call awk command. I set some variables in the script and I would like to use them up within AWK as well. Unfortunately AWK seems to forget all the variable values outside of its own... (1 Reply)
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I am passing a varaible to from Shell to awk then I am doing some maniplation for that variable inside awk. I want that maniplated variable value back to shell , Is this possible .Please let me know. (12 Replies)
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6. Shell Programming and Scripting
Read parameter from a text file with one line which stored the date value like 20080831; below is the awk command I used
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I'm trying to store the response from a nawk command inside of a ksh script. The command is:
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Hi
I want to pass variables with the NR function in awk command.
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I know this topic has been dealt with previously, but the solutions I've seen don't work for me apparently.
I need to pass a variable defined in the shell to one in awk:
$ echo $var1
3
$ cat aaa
aaa 1
bbb 2
ccc 3
ddd 4
eee 5I've tried this, without success:
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Hello,
May i please know how do i pass the shell variable to awk expression in the below script. It is returning null
#!/bin/bash
UNINUM=720922
UNINUM_DESC=`awk -F'|' -v UNINUM=$2 '/UNINUM/ {print $4}' datafile`
echo $UNINUM_DESC
datafile
4|First|720194|asdasdad
4|First|720735|asdasdsa... (8 Replies)
Discussion started by: Ariean
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LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)