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Top Forums Shell Programming and Scripting Printing entire field, if at least one row is matching by AWK Post 302562514 by CarloM on Friday 7th of October 2011 06:47:38 AM
Old 10-07-2011
I imagine there are much neater ways, but this seems to work:
Code:
 awk -vMYCOL="ddd" '{if (NR == 1) { for (i=1;i<=NF;i++) { if ($i == MYCOL) { mycolnum = i } } } { print $mycolnum }}' file1

EDIT: Changed a bit to output the header line.

Also, if there are no matching columns it just prints everything - if you want no output you'd need an additional if:
Code:
 awk -vMYCOL="ddd" '{if (NR == 1) { for (i=1;i<=NF;i++) { if ($i == MYCOL) { mycolnum = i } } } { if (mycolnum) { print $mycolnum }}}' file1


Last edited by CarloM; 10-07-2011 at 08:02 AM.. Reason: Output the header
This User Gave Thanks to CarloM For This Post:
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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