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Top Forums Shell Programming and Scripting Find and replace a word in all the files (that contain the word) under a directory Post 302561643 by filter on Tuesday 4th of October 2011 05:45:04 PM
Old 10-04-2011
Find and replace a word in all the files (that contain the word) under a directory

Hi Everyone,

I am looking for a simple way for replacing all the files under a directory that use the server "xsgd1234dap" with "xsdr3423pap".

For Example:

In the Directory,
Code:
[xgdfy3487]$pwd
/home/nick

[xgdfy3487] $ grep -l "xsgd1234dap" *.sh | wc -l
119

I have "119" files that are still using "xsgd1234dap" but Instead I would like replace it with "xsdr3423pap" for all the files (119).

Could someone please tell me any easier way to do this instead of manually doing it file by file.

I would really appreciate you time and thoughts.

Last edited by filter; 10-04-2011 at 06:45 PM.. Reason: Adding Code tags
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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