I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename?
#!/bin/bash
filename=`echo $0`
/usr/bin/sed '/#include/ {
i\
the filename is `$filename`
}' $1
exit 0 (8 Replies)
When script is running you only see when some of the commands are not successfull.
Is there a way to see which command are executed and to show the substitution of variables as every line is executed ? (3 Replies)
For example I have variable like below
echo $OUTPUT
/some/path/`uname -n`
when I try to use the variable OUTPUT like below
cd $OUTPUT or cd ${OUTPUT}
I am getting bad substituion error message
$ cd $OUTPUT
ksh: cd: bad substitution
$ cd ${OUTPUT}
ksh: cd: bad substitution
... (1 Reply)
Hi Jim,
The following script is in working state. But i m having one more problem with awk cmd. Could you tell me how to use any variable inside awk or how to take any variable value outside awk.
My problem is i want to maintain one property file in which i am declaring variable value into that... (12 Replies)
Hi,
I am trying to do the following thing
var='date'
$var
Above command substitutes date for and in turn runs the date command and i am getting the todays date value.
I am trying to do the same thing as following, but facing some problems,
unique_host_pro="sed -e ' /#/d'... (3 Replies)
Hello All,
I don't write scripts very often, and in this case I am stumped, although it may be a bug in the version of bash I have to use (it's not my system).
I want to extract a specific string snippet from a block of text (coming from a log file) that is dependent on a bunch of other... (1 Reply)
#!/bin/bash
#...
for i in `ls -c1 /usr/share/applications`
do
name="cat $i | grep ^Name= | cut -d = -f2"
echo $name
#...
done
Now inside name as output is present:
while i want only the result of the command.
Ideally i would like obtain that information using only bash ... or... (8 Replies)
Hello all. This is my first post/question on this site.
I’m a new Systems Analyst with previous experience with BASH. Although now I'm using AIX, and I’m trying to get a feel for the Korn shell (for those of you that don’t know AIX only uses the KORN shell).
I hope I put this into the correct... (10 Replies)
Hi,
I am not able to get output for find command if there are variables defined inside -name option .
Please check below example
1)
###VARIABLES DEFINED
process="fast"
temperature="125c"
voltage="0p935v"
2) I don't get output for below find command
find -L <PATH> -type f \( -name... (2 Replies)
Is it possible to store a command inside a variable?
i want this piece to be stored inside a variable, so i can use it later in a different command
$u | cut -d " " -f 2
var="$u | cut -d " " -f 2"
eval $var
I tried to use eval but I receive this error:
-f 2: command not found
... (5 Replies)
Discussion started by: velos
5 Replies
LEARN ABOUT POSIX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)