Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
drwxr-xr-x 40 root sys 1024 25-08-2009 22:19 usr
drwxr-xr-x 43 root sys ... (4 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Hi,
I have the variable "$date_update" in that form:
2011-12-31T13:00:09Z and I would like to change it to
31/12/2011 13:00:09 (Date and Time separated by a blank).
Does anyone has a simple solution for that? (using Korn Shell)
Cheers
Jurgen (4 Replies)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT DEBIAN
convert::nls_date_format
Convert::NLS_DATE_FORMAT(3pm) User Contributed Perl Documentation Convert::NLS_DATE_FORMAT(3pm)NAME
Convert::NLS_DATE_FORMAT - Convert Oracle NLS_DATE_FORMAT <-> strftime Format Strings
SYNOPSIS
use Convert::NLS_DATE_FORMAT qw(oracle2posix posix2oracle);
my $strptime = oracle2posix($NLS_DATE_FORMAT);
$NLS_DATE_FORMAT = posix2oracle($strftime);
DESCRIPTION
Convert Oracle's NLS_DATE_FORMAT string into a strptime format string, or the reverse.
Functions
oracle2posix
Takes an Oracle NLS_DATE_FORMAT string and converts it into formatting string compatible with "strftime" or "strptime".
my $format = oracle2posix('YYYY-MM-DD HH24:MI:SS'); # '%Y-%m-%d %H:%M:%S'
Character sequences that should not be translated may be enclosed within double quotes, as specified in the Oracle documentation.
my $format = oracle2posix('YYYY-MM-DD"T"HH24:MI:SS'); # '%Y-%m-%dT%H:%M:%S'
posix2oracle
Takes a "strftime" or "strptime" formatting string and converts it into an Oracle NLS_DATE_FORMAT string. It is possible to create
strings which Oracle will not accept as valid NLS_DATE_FORMAT strings.
my $format = posix2oracle('%Y-%m-%d %H:%M:%S'); # 'YYYY-MM-DD HH24:MI:SS'
EXPORT
None by default. "oracle2posix" and "posix2oracle" when asked.
SEE ALSO
DateTime::Format::Oracle.
AUTHOR
Nathan Gray, <kolibrie@cpan.org>
COPYRIGHT AND LICENSE
Copyright (C) 2005, 2006, 2011, 2012 Nathan Gray
This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself, either Perl version 5.8.4 or,
at your option, any later version of Perl 5 you may have available.
perl v5.14.2 2012-01-18 Convert::NLS_DATE_FORMAT(3pm)