09-20-2011
Help with checking that 2 variables contain matching characters
hi
i am writing a hangman script and am having trouble checking the correct letters against the word
i need the script to compare the word against the letters guessed that are correct so once all the letters within the word have been guessed it will alow me to create a wining senario
eg
word
hello
guessed
adhewlso
this would be a correct result because all the letters within the word have been guessed
any help would be appreciated im stumped by this
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BOGGLE(6) Games Manual BOGGLE(6)
NAME
boggle - play the game of boggle
SYNOPSIS
/usr/games/boggle [ + ] [ ++ ]
DESCRIPTION
This program is intended for people wishing to sharpen their skills at Boggle (TM Parker Bros.). If you invoke the program with 4 argu-
ments of 4 letters each, (e.g. "boggle appl epie moth erhd") the program forms the obvious Boggle grid and lists all the words from
/usr/dict/words found therein. If you invoke the program without arguments, it will generate a board for you, let you enter words for 3
minutes, and then tell you how well you did relative to /usr/dict/words.
The object of Boggle is to find, within 3 minutes, as many words as possible in a 4 by 4 grid of letters. Words may be formed from any
sequence of 3 or more adjacent letters in the grid. The letters may join horizontally, vertically, or diagonally. However, no position in
the grid may be used more than once within any one word. In competitive play amongst humans, each player is given credit for those of his
words which no other player has found.
In interactive play, enter your words separated by spaces, tabs, or newlines. A bell will ring when there is 2:00, 1:00, 0:10, 0:02, 0:01,
and 0:00 time left. You may complete any word started before the expiration of time. You can surrender before time is up by hitting
'break'. While entering words, your erase character is only effective within the current word and your line kill character is ignored.
Advanced players may wish to invoke the program with 1 or 2 +'s as the first argument. The first + removes the restriction that positions
can only be used once in each word. The second + causes a position to be considered adjacent to itself as well as its (up to) 8 neighbors.
4th Berkeley Distribution May 20, 1985 BOGGLE(6)