Given a file such as this I need to remove the duplicates.
00060011 PAUL BOWSTEIN ad_waq3_921_20100826_010517.txt
00060011 PAUL BOWSTEIN ad_waq3_921_20100827_010528.txt
0624-01 RUT CORPORATION ad_sade3_10_20100827_010528.txt
0624-01 RUT CORPORATION ... (13 Replies)
Here is the fix for the recent Google changes to their pagerank API. For example, in the List Rank Dashboard Widget Wordpress Plugin (Version 1.7), in this plugin file:
list-rank-dashboard-widget/wp-list-rank-class.php
in this function:
function getGooglePR($url)
Change this line:
... (0 Replies)
Hi All,
I have following html code
<TR><TD>9</TD><TD>AR_TVR_TBS </TD><TD>85000</TD><TD>39938</TD><TD>54212</TD><TD>46</TD></TR>
<TR><TD>10</TD><TD>ASCV_SMY_TBS </TD><TD>69880</TD><TD>33316</TD><TD>45698</TD><TD>47</TD></TR>
<TR><TD>11</TD><TD>ARC_TBS ... (9 Replies)
I have a tab delimited text file that looks like the following:
ERBB3 0.00097
IL31RA 0.000972
SETD5 0.000972
MCART1 0.000973
CENPJ 0.000973
FNDC6 0.000974
I want to assign a number to each row based on the value in the last column (in the order of increasing value so that the first row... (3 Replies)
Hi,
I have a similar input format-
A_1 2
B_0 4
A_1 1
B_2 5
A_4 1
and looking to print in this output format with headers. can you suggest in awk?awk because i am doing some pattern matching from parent file to print column 1 of my input using awk already.Thanks!
letter number_of_letters... (5 Replies)
Hi,
I have a table to be imported for R as matrix or data.frame but I first need to edit it because I've got several lines with the same identifier (1st column), so I want to sum the each column (2nd -nth) of each identifier (1st column)
The input is for example, after sorted:
K00001 1 1 4 3... (8 Replies)
Hi All,
I am trying to select the rows in a fixed width file based on values in the columns.
I want to select only the rows if column position 3-4 has the value AB
I am using cut command to get the column values. Is it possible to check if cut -c3-4 = AB is true then select only that... (2 Replies)
Hello everyone,
I am using ksh on Solaris 10 and I'm gathering data in a CSV file that looks like this:
20170628-23:25:01,1,0,0,1,1,1,1,55,55,1
20170628-23:30:01,1,0,0,1,1,1,1,56,56,1
20170628-23:35:00,1,0,0,1,1,2,1,57,57,2
20170628-23:40:00,1,0,0,1,1,1,1,58,58,2... (6 Replies)
Hi All ,
I am having an input file as stated below
Input file
6 ddk/djhdj/djhdj/Q 10 0.5
dhd/jdjd.djd.nd/QB 01 0.5
hdhd/jd/jd/jdj/Q 10 0.5
512 hd/hdh/gdh/Q 01 0.5
jdjd/jd/ud/j/QB 10 0.5
HD/jsj/djd/Q 01 0.5
71 hdh/jjd/dj/jd/Q 10 0.5
... (5 Replies)
Discussion started by: kshitij
5 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)