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Full Discussion: Rank based on column in Unix
Top Forums Shell Programming and Scripting Rank based on column in Unix Post 302556645 by sk1418 on Monday 19th of September 2011 08:53:28 AM
Old 09-19-2011
here it is:
Code:
kent$  echo "1783747|091411|1000
1783747|091411|2000
1783747|091411|2000
1783747|091411|2000
1783747|091411|3000
1783747|091411|4000
1783747|091411|5000
1783747|091411|6000
1783747|091411|7000
1783747|091411|8000
1783747|091411|9000
1783747|091411|10000"|awk -F'|' '{if($3>x){x=$3;i++};print $0"|"i}'
1783747|091411|1000|1
1783747|091411|2000|2
1783747|091411|2000|2
1783747|091411|2000|2
1783747|091411|3000|3
1783747|091411|4000|4
1783747|091411|5000|5
1783747|091411|6000|6
1783747|091411|7000|7
1783747|091411|8000|8
1783747|091411|9000|9
1783747|091411|10000|10


Last edited by sk1418; 09-19-2011 at 09:58 AM..
This User Gave Thanks to sk1418 For This Post:
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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