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Top Forums Shell Programming and Scripting sorting the datafile in an order given in second datafile Post 302553303 by CAch on Wednesday 7th of September 2011 07:27:26 AM
Old 09-07-2011
sorting the datafile in an order given in second datafile

Hi,

I have two files:

first input file is having 7-8 columns,

Quote:
1 a rew sdf ghd 234 gfd 345
3 f hjk kln ghj 879 nkj 989
7 c dns esd lkn 765 nkc 093
4 d bhj asd klj 231 kljn 211
and second data file is like

Quote:
a
b
c
d
e
f
g
.
.
I want to arrange my datafile1 in the order given in second data file, by comparing the seconddatafile with the second column of first file and print the entire line....also if any string (b in this case) is absent..it must print absent in first lane

The output must be like:

Quote:
1 a rew sdf ghd 234 gfd 345
ABSENT
7 c dns esd lkn 765 nkc 093
4 d bhj asd klj 231 kljn 211
ABSENT
3 f hjk kln ghj 879 nkj 989
Thanks in advance.....
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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