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Top Forums Shell Programming and Scripting Sed or awk : pattern selection based on special characters Post 302552982 by yazu on Tuesday 6th of September 2011 09:15:56 AM
Old 09-06-2011
Code:
echo '//mytestserver.bon.com' | sed -r 's //([^.]*).* \1 '
mytestserver

Smilie
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GLOB_MATCH(9)						       libata Core Internals						     GLOB_MATCH(9)

NAME
glob_match - match a text string against a glob-style pattern SYNOPSIS
int glob_match(const char * text, const char * pattern); ARGUMENTS
text the string to be examined pattern the glob-style pattern to be matched against DESCRIPTION
Either/both of text and pattern can be empty strings. Match text against a glob-style pattern, with wildcards and simple sets: ? matches any single character. * matches any run of characters. [xyz] matches a single character from the set: x, y, or z. [a-d] matches a single character from the range: a, b, c, or d. [a-d0-9] matches a single character from either range. The special characters ?, [, -, or *, can be matched using a set, eg. [*] Behaviour with malformed patterns is undefined, though generally reasonable. SAMPLE PATTERNS
"SD1?", "SD1[0-5]", "*R0", "SD*1?[012]*xx" This function uses one level of recursion per '*' in pattern. Since it calls _nothing_ else, and has _no_ explicit local variables, this will not cause stack problems for any reasonable use here. RETURNS
0 on match, 1 otherwise. AUTHOR
Jeff Garzik Author. COPYRIGHT
Kernel Hackers Manual 3.10 June 2014 GLOB_MATCH(9)
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