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Full Discussion: Memory fault(coredump)
Homework and Emergencies Homework & Coursework Questions Memory fault(coredump) Post 302552520 by kermit on Sunday 4th of September 2011 07:55:43 AM
Old 09-04-2011
Code:
#include <stdio.h>

main()
{
        int c;
    int nl_cnt = 0;

        while((c = getchar()) != EOF){

                if(c == '\n'){
                nl_cnt++;
                printf("%d ", nl_cnt);}

                putchar(c);

        }

}

Quote:
Originally Posted by heywoodfloyd
how do I get the numbers and the code to line up correctly?
Your logic is a bit off. Check if c is a newline. If it is, print c, and then print a line number. Otherwise, just print c. You might also want to print a line number before your loop so that your first line is numbered.

A couple of other things:
  1. You should have warnings turned on for your compiler. This would have helped you catch your initial problem much easier. For example, if you were using gcc to compile, you would use (at minimum) the -Wall and -Wextra switches, e.g.,
    Code:
    gcc -Wall -Wextra -o myprog myprog.c

    Consult your manual pages for specific details about your system.
  2. The second is more nitpicky, but still good to know. The above program is not exactly conforming C - not to C89, and not to C99. In C89, main may be declared as above, but must have an explicit return statement. Under C99, main must be declared as one of the following:
    Code:
    int main(void)
    int main(int argc, char *argv[]) /* int main(int argc, char **argv)
                                 * is also acceptable
                                 */

    Additionally, under C89, an explicit return at the end of main is required. In C99, it is not, and if not provided, a return value of zero is implied. Had you turned your compiler warnings on, it may have told you that you did not return a value from main in your 'cat -n' program.
 

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isaexec(3C)						   Standard C Library Functions 					       isaexec(3C)

NAME
isaexec - invoke isa-specific executable SYNOPSIS
#include <unistd.h> int isaexec(const char *path, char *const argv[], char *const envp[]); DESCRIPTION
The isaexec() function takes the path specified as path and breaks it into directory and file name components. It enquires from the running system the list of supported instruction set architectures; see isalist(5). The function traverses the list for an executable file in named subdirectories of the original directory. When such a file is located, execve() is invoked with argv[] and envp[]. See exec(2). RETURN VALUES
If no file is located, isaexec() returns ENOENT. Other return values are the same as for execve(). EXAMPLES
Example 1: Example of isaexec() function. On a system whose isalist is sparcv7 sparc the program int main(int argc, char *argv[], char *envp[]) { return (isaexec("/bin/thing", argv, envp)); } will look first for an executable file named /bin/sparcv7/thing, then for an executable file named /bin/sparc/thing. It will invoke execve() on the first executable file it finds named thing. On that same system, a program called /u/bin/tofu can cause either /u/bin/sparcv7/tofu or /u/bin/sparc/tofu to be invoked using the follow- ing code: int main(int argc, char *argv[], char *envp[]) { return (isaexec(getexecname(), argv, envp)); } ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |MT-Level |Safe | +-----------------------------+-----------------------------+ |Interface Stability |Stable | +-----------------------------+-----------------------------+ SEE ALSO
exec(2), getexecname(3C), attributes(5), isalist(5) SunOS 5.10 20 Mar 1998 isaexec(3C)
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