Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Print first, second, every nth, and last record Post 302552409 by alister on Friday 2nd of September 2011 10:50:55 PM
Old 09-02-2011
Nah. Embarassing is what happened to me a couple days ago. I overlooked a requirement and incorrectly critiqued two other suggestions in the thread. Fortunately (I think), I was able to edit/delete my post before it was seen. Smilie
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Using sed to extract Nth record?

I have a comma-separated record and I'd like to use sed to pull the Nth record from it. It seems like it'd need to be something like this: sed -n 's/'"\,$1\,"'/&/p' Am I close? (3 Replies)
Discussion started by: doubleminus
3 Replies

2. UNIX for Advanced & Expert Users

Print Full record and substring in that record

I have i got a requirement like below. I have input file which contains following fixed width records. 00000000000088500232007112007111 I need the full record and concatenated with ~ and characters from 1to 5 and concatenated with ~ and charactes from 10 to 15 The out put will be like... (1 Reply)
Discussion started by: ukatru
1 Replies

3. Shell Programming and Scripting

Get Nth record from last line

I have a growing file . I knew only last few lines which is constant for evey job run. I'd need to pull the Nth record from the last line. In this case i should not use search pattern. (2 Replies)
Discussion started by: ford2020
2 Replies

4. Shell Programming and Scripting

How to Print from nth field to mth fields using awk

Hi, Is there any short method to print from a particular field till another filed using awk? Example File: File1 ==== 1|2|acv|vbc|......|100|342 2|3|afg|nhj|.......|100|346 Expected output: File2 ==== acv|vbc|.....|100 afg|nhj|.....|100 (8 Replies)
Discussion started by: machomaddy
8 Replies

5. Shell Programming and Scripting

Print every nth line

Dear all, How to print every nth line. File like this: File input: 1 1 1 1 1 1 2 2 2 3 3 3 3 3 3 (3 Replies)
Discussion started by: attila
3 Replies

6. UNIX for Dummies Questions & Answers

Print Nth to last field

Hey, I'm sure this is answered somewhere but my Googling has turned up nothing. I have a file with data in the following format: <desription of event> at <time and date>The desription of the event is variable length and hence when the list is displayed it is hard to easily see the date (and... (8 Replies)
Discussion started by: RECrerar
8 Replies

7. Shell Programming and Scripting

Print nth line in a file

Bash/Oracle Linux 6.4 A basic requirement. How can I get nth line of a file printed ? Can I use grep in this case ? Example: In the below file, 12th line is "Kernel parameter check passed for rmem_max" . I just want the 12 line to be printed. # cat sometext.txt Kernel version check... (2 Replies)
Discussion started by: John K
2 Replies

8. AIX

Print nth previous line after match

Please help me print nth line after match awk or sed one line command. (3 Replies)
Discussion started by: sushma123
3 Replies

9. UNIX for Beginners Questions & Answers

Print lines based upon unique values in Nth field

For some reason I am having difficulty performing what should be a fairly easy task. I would like to print lines of a file that have a unique value in the first field. For example, I have a large data-set with the following excerpt: PS003,001 MZMWR/ L-DWD// * PS003,001... (4 Replies)
Discussion started by: jvoot
4 Replies

10. UNIX for Beginners Questions & Answers

Need to print nth till last column of ls output using sed

I wish to print first, third and sixth till the last column from the output of ls command ls -ltr /app/deploy.yml -rw-rw-r-- 1 user1 dba 27342 Aug 28 10:17 /app/deploy.yml Desired Output: Below command gives me the desired output. ls -ltr /app/deploy.yml | awk '{$2=$4=$5=""; print... (6 Replies)
Discussion started by: mohtashims
6 Replies
lchage(1)						      General Commands Manual							 lchage(1)

NAME
lchage - Display or change user password policy SYNOPSIS
lchage [OPTION]... user DESCRIPTION
Displays or allows changing password policy of user. OPTIONS
-d, --date=days Set the date of last password change to days after Jan 1 1970. Set days to -1 to disable password expiration (i.e. to ignore --mindays, and --maxdays and related settings). Set days to 0 to enforce password change on next login. (This also disables password expiration until the password is changed.) -E, --expire=days Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -I, --inactive=days Disable the account after days after password expires (after the user is required to change the password). Set days to -1 to keep the account enabled indefinitely after password expiration. -l, --list Only list current user's policy and make no changes. -m, --mindays=days Require at least days days between password changes. Set days to 0 or -1 to disable this requirement. If this value is larger than the value set by --maxdays, the user cannot change the pasword. -M, --maxdays=days Require changing the password after days since last password change. Set days to -1 to disable password expiration. -W, --warndays=days Start warning the user days before password expires (before the user is required to change the password). Set days to 0 or -1 to disable the warning. EXIT STATUS
The exit status is 0 on success, nonzero on error. NOTES
Note that "account expiration" (set by --expire) is distinct from "password expiration" (set by --maxdays). Account expiration happens on a fixed date regardless of password changes. Password expiration is relative to the date of last password change. libuser Nov 8 2012 lchage(1)
All times are GMT -4. The time now is 02:39 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy