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Full Discussion: Array and field separator
Top Forums Shell Programming and Scripting Array and field separator Post 302551669 by radoulov on Wednesday 31st of August 2011 09:01:51 AM
Old 08-31-2011
The shell field/word splitting occurs only on expansion.

From the manual pages of bash:
Quote:
Word Splitting
The shell scans the results of parameter expansion, command substitution, and arithmetic expansion that did not
occur within double quotes for word splitting.
[...]

Note that if no expansion occurs, no splitting is performed.
So:

Code:
4.1.10(4)-release$ IFS=+
4.1.10(4)-release$ a=( one+two )
4.1.10(4)-release$ echo "${a[0]}"
one+two

Use some kind of expansion:

Code:
4.1.10(4)-release$ s='one+two'
4.1.10(4)-release$ a=( $s )
4.1.10(4)-release$ echo "${a[0]}"
one

Consider the following:

Code:
elements='hello world+sunny'

# $elements is not quoted so it is
# subject to word splitting
# based on the current value
# of IFS

array_test=( $elements )

for elem in "${array_test[@]}"; do
  printf '%s\n' "$elem"
done

printf '\nChanging IFS to %s\n\n' +

IFS=+

# we need to reassign 
# in order to perform word
# splitting based on the 
# new IFS value

array_test=( $elements )

for elem in "${array_test[@]}"; do
  printf '%s\n' "$elem"
done


This is the output:


Code:
4.1.10(4)-release$ ./s
hello
world+sunny

Changing IFS to +

hello world
sunny

With recent versions of bash you could use something like this too:


Code:
4.1.10(4)-release$ IFS=+ read -ra arr <<<'one+two'
4.1.10(4)-release$ printf '%s\n' "${arr[0]}"
one


Last edited by radoulov; 08-31-2011 at 10:12 AM..
This User Gave Thanks to radoulov For This Post:
 

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