Hi,
how can find length of file names in a directory.
Examp:
I have a directory with name "d1".
directory: d1
files:
aaa.log
bbb.log
abcd.log
abcdef.log
I wold like out put like:
file name legnth
aaa.log 3
bbb.log 3
abcd.log 4
abcdef.log 5 (5 Replies)
Hi,
I have to copy a set of files abc* in /path/ to /path1/ as abc*_bkp.
The list of files appear as follows in /path/:
abc1
xyszd
abc2
re2345
abcx
..
.
abcxyz
I have to copy them (abc* files only) into /path1/ as:
abc1_bkp
abc2_bkp
abcx_bkp
..
. (6 Replies)
Hi,
I am trying to find the content of file using grep and find command and list only the file names
but i am getting entire file list of files in the directory
find . -exec grep "test" {} \; -ls
Can anyone of you correct this (2 Replies)
Hello,
How to find the list of 5 largest(size wise) file in current directory?i tried using
ls -l | sort -t " " -r +5 -6 -n | head -5
but this is not giving correct output as ls -l command gives 1 extra line of output that is how many total files are there!so by running the above... (4 Replies)
I have a script that generates a variable with the location of a file and its complete path. What i want to do is to "cd" to the directory where that file is located using the path name of the file. GIS has absolutely failed me.
For example when i run my script it generates a variable called... (1 Reply)
I have some files, those are abbreviated (ed,ea, and bi)
company_ed_20100719.txt
company_ea_20100719.txt
company_bi_20100719.txt
I would like to rename these files by replacing
ed with EmployeeDetails
ea with EmployeeAddress
bi with BankInfomration
as
company_... (3 Replies)
hello I'm doing a unix program and i'm using many file csv.in each csv file the colums are separated by ";" I would like to know the position of a pattern. For example for a line yyyy, bbbb, cccc; ddddd;eeee. I will like for example by finding the position of the pattern "cccc" and the response is... (6 Replies)
I need assistance with following requirement, I am new to Unix.
I want to do the following task but stuck with file creation date(sysdate)
Following is the requirement
I need to create a script that will read the abc/xyz/klm folder and look for *.err files for that day’s date and then send an... (4 Replies)
Discussion started by: PreetArul
4 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)