I need to find files that have the ending of .out and that are older than 20 days. However, I cannot use find as I do not want to search in the directories that are underneath the directory that I am searching in.
How can this be done?? Find returns files that I do not want. (2 Replies)
Hi,
I have dummies questions:
My script here can find the files in any directories older than 30 days then it will delete the files but not the directories. I would like to also be able to delete the directories that hold old files more than 30 days not just the files itself.
find . -type f... (2 Replies)
Dear Friends,
I have two queries.
1) I want to see the list of folders which were created 29 days ago.
2) I want to see the folders in which last created file is older than 29 days.
Can it be done?
Thank you in advance
Anushree (4 Replies)
What command arguments I can use in unix to list files older than 10 days in my current directory, but I don't want to list the hidden files.
find . -type f -mtime +15 -print will work but, it is listing all the hidden files., which I don't want. (4 Replies)
Hello,
I have a script which finds files in a directory that are older than 30 days and remove them.
The problem is that these files are too many and when i run this command:
find * -mtime +30 | xargs rm
I run this command inside the directory and it returns the error:
/usr/bin/find:... (8 Replies)
Hello All,
Can someone please help me out in creating the find command to search and delete files older than 1 days at a desired location.
Thanks in advance for your help. (3 Replies)
Hi
I'm trying to writte a script (crontab) to copy files from one location to another... this is what i have:
find . -name "VPN_CALLRECORD_20130422*" | xargs cp "{}" /home/sysadm/patrick_temp/
but that is not working this is the ouput:
cp: Target... (5 Replies)
Hi All,
Problem Statement:Find all log files under all file systems older than 2 days and zip them. Find all zip files older than 3days and remove them. Also this has to be set under cron.
I have a concerns here
find . -mtime +2 -iname "*.log" -exec gzip {}
Not sure if this will work as... (4 Replies)
Hi,
I have multiple files in my log folder. e.g:
a_m1.log
b_1.log
c_1.log
d_1.log
b_2.log
c_2.log
d_2.log
e_m1.log
a_m2.log
e_m2.log
I need to keep latest 10 instances of each file.
I can write multiple find commands but looking if it is possible in one line.
m file are monthly... (4 Replies)
Discussion started by: wahi80
4 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)