I am very sorry for not being clear. I realized that I really don't make much sense in my first post.
I am trying to come up with a solution but got stuck in the file looping operation. This is what I intend to do.
Step by Step Procedure:
1. Open 1.dat
2. Open A.txt
3. Take the first word from A.txt (this word could be single or compound word like random access memory)
4. Search that first word in 1.dat
5. If the first word is found then store the value as 1 (in my case A.txt means 1, B.txt means 2, C.txt means 3 until L.txt which is 12)
6. If the second word is found from A.txt in 1.dat then add 1 to the previous value
7. If again another word from A.txt matches in 1.dat, add 1 again to the previous value and keep adding them as they are found in 1.dat
8. When A.txt is EOF, take B.txt now and search 1.dat again (from beginning) and as and when a word is found keep adding "2" to the previous addition counter.
9. When B.txt is EOF, take C.txt and search 1.dat again. If any word which is present in C.txt and also in 1.dat, now keep adding "3" to the previous counter value as and when the match occurs.
10. Keep doing it until L.txt and for L.txt keeping adding 12 as and when matching occurs.
12. Now, take the mean (average) that is entire number of match that has occurred from A.txt to L.txt
13. Store this mean in 1.num
14. Now, take 2.dat and repeat the procedure from A.txt until L.txt
One thing that is important: When A.txt is being read and match occurs I only keep adding 1 as and when match happens else 0. For B.txt its 2, for C.txt its 3 etc until L.txt
Example.
Consider A.txt
Consider B.txt
Consider 1.dat
I read A.txt and extract "computer" from it. A.txt is 1
I then search "computer" in the entire text 1.dat and luckily find it in 1.dat. I only have to find match once even if "computer" exists several times. Now, I store this value in some array or variable as 1
I then goto line 2 of A.txt and extract "random access memory". I again search 1.dat for the presence of "random access memory" and BINGO!! found it again and store in the array or variable as 1 as it is in line in A.txt
I do it for entire A.txt and now I find none. So, I goto B.txt
I have an addition counter. So, now my addition counter has 2 (1+1) until now.
Now, I read B.txt
"rom" found in text and hence now add "2" to the previsous addition counter.
"flash" found again add 2 again to the previous counter.
Now I open C.txt and keep adding 3 if found.
Suppose, none of the other TXT files contain any matching words. So, my final addition counter is 6 (1+1+2+2=6 from A.txt and B.txt matches) and mean is 6/4 = 1.5 and store this value in 1.num. (4 is the number of times matches occur)
When all done until L.txt, then I begin the same procedure with 2.dat (and store result in 2.num) until all DAT files have been read.
I think the complexity has increased due to many files else its very simple.
---------- Post updated 08-27-11 at 01:26 PM ---------- Previous update was 08-26-11 at 11:48 PM ----------
Hi All,
After bit of work, I came up with my own code. I am not a PhD in shell scripting but can do farely well in C (I know this section of the forum is not for C codes!). I am pasting my code below so that in future if any one who comes across a similar problem; one can use my code straight away or with a bit of modification according to the needs.
This is what one needs to do in order to run this code.
Place all the .txt and .dat files in one directory and run this code. One case see a file named average_values.res created when the code completes execution. I have used GNU GCC for compiling and creating the binary.
In case any one cannot understand the code, kindly comment here and I shall happily respond.
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