using an awk internal variable as parameter for an external array Post: 302550303

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Top Forums Shell Programming and Scripting using an awk internal variable as parameter for an external array Post 302550303 by MotAah on Thursday 25th of August 2011 09:12:40 AM

08-25-2011

Registered User

using an awk internal variable as parameter for an external array

Hello,

I am running a bash script under linux which first defines an CA-array like

Code:

j=0
num1=120.00
num2=10.00
until [$j -gt 5 ]
do
  CA[$j]='echo $num1 + $j*$num2'
  j=$[$j+1]
done

within the later awk section of this same script I want to read data from a file. If the value of the second column is equal to the value of CA[0 to 5] the array MF[0 to 5] should read the value from column 59:

Code:

awk '
BEGIN {
  ...
  i=0
  while ( i<5 ) {
    if ( match($2,/^'${CA[1]}'/) ) { MF[i] = $59 }
      i = i + 1
  }
}
END ' ${FILE}

As long in the bold written part the parameter of the array is fixed to certain value (here "1") the script works fine. In later stage I do want to read dozend of lines from the file and not only 5!

Does anyone know how I do have to change the script ('${CA[1]}') in order to have "i" of the awk loop to define the parameter fo the external array CA? Any help or work arround is appreciated.

Regards,

MotAah

Last edited by Scott; 08-25-2011 at 10:14 AM.. Reason: Code tags

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