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Top Forums Shell Programming and Scripting AWK/SED print if 2nd character in a column is greater than 0 Post 302548563 by spacemtn5 on Thursday 18th of August 2011 06:03:49 PM
Old 08-18-2011
That helped me to some extent. Thank you. Is there a way we can print rows whose $8 is greater than 10 secs. $8 is time in seconds, format = (n), parenthesis included.

I did a awk '$8 >"(10)"' access.log which also printed rows < (10) value. Any ideas?
 

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DB2_FIELD_WIDTH(3)							 1							DB2_FIELD_WIDTH(3)

db2_field_width - Returns the width of the current value of the indicated column in a result set

SYNOPSIS
int db2_field_width (resource $stmt, mixed $column) DESCRIPTION
Returns the width of the current value of the indicated column in a result set. This is the maximum width of the column for a fixed-length data type, or the actual width of the column for a variable-length data type. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns an integer containing the width of the specified character or binary data type column in a result set. If the specified column does not exist in the result set, db2_field_width(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3). PHP Documentation Group DB2_FIELD_WIDTH(3)
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