Hi,
I have an expression using grep and nawk that captures the ID number of a given Unix process. It gets printed to screen but I don't know how to declare a variable to this returned value!
For example,
ps -ef|grep $project | grep -v grep | nawk '{print $2}'
This returns my number. How... (2 Replies)
I have a class with an integer pointer, which I have not initialized to NULL in the constructor. For example:
class myclass
{
private:
char * name;
int *site;
}
myclass:: myclass(....)
: name(NULL)
{
.....
}
other member function “delete “ the variable before... (2 Replies)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hello,
I am in following situation.-
COUNT=`ls -l | wc -l`
echo $COUNT
---> 26
NO_OF_FILES=$COUNT-1
echo $NO_OF_FILES
---> 26-1
Here, I want the output to be 25. How could I do this. It seems simple, but I am not getting it. Please help me. (2 Replies)
Hi !
I'm looking for a way to transform certain floating point numbers in a one-line, variable length file to integers.
I can do this in a crude way with sed :
sed -e 's/0\.\(\):/\1:/g' -e 's/0\.0\(\):/\1:/g' -e 's/1\.000:/100:/g' myfile ... but this doesn't handle the rounding correctly.
... (3 Replies)
I would like to know the maximum integer that a variable can hold. Actually one of my variable holds value 2231599773 and hence the script fails to process it.Do we have any other data type or options available to handle this long integers? (9 Replies)
I read 3 variables from from Inputfile.txt the third one "startnumber" is a number when i compare it with 9 ($startnumber -le 9) it give's me a "unary operator expected", i know that -le is for number comparison. What i need is to convert $startnumber to integer (i have try to do it with expr but... (8 Replies)
Hi Guys,
i guess there is a several ways to grub the strings from date and time
like THISMONTH='/bin/date +%m'
but the hard part is to add or sub that string to a variable
i tried to use let command
TWOMONTHSAGO=$THISMONTH
declare -i TWOMONTHSAGO
let TWOMONTHSAGO-=2
but there... (1 Reply)
Hi Folks -
Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64
I have a process that determines the start and end load periods for an Oracle data load process.
The variables used are as follows follows:
They are populated like such:
However, the load requires the month to be the... (11 Replies)
Discussion started by: SIMMS7400
11 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)