Hi,
I have an expression using grep and nawk that captures the ID number of a given Unix process. It gets printed to screen but I don't know how to declare a variable to this returned value!
For example,
ps -ef|grep $project | grep -v grep | nawk '{print $2}'
This returns my number. How... (2 Replies)
I have a class with an integer pointer, which I have not initialized to NULL in the constructor. For example:
class myclass
{
private:
char * name;
int *site;
}
myclass:: myclass(....)
: name(NULL)
{
.....
}
other member function “delete “ the variable before... (2 Replies)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hello,
I am in following situation.-
COUNT=`ls -l | wc -l`
echo $COUNT
---> 26
NO_OF_FILES=$COUNT-1
echo $NO_OF_FILES
---> 26-1
Here, I want the output to be 25. How could I do this. It seems simple, but I am not getting it. Please help me. (2 Replies)
Hi !
I'm looking for a way to transform certain floating point numbers in a one-line, variable length file to integers.
I can do this in a crude way with sed :
sed -e 's/0\.\(\):/\1:/g' -e 's/0\.0\(\):/\1:/g' -e 's/1\.000:/100:/g' myfile ... but this doesn't handle the rounding correctly.
... (3 Replies)
I would like to know the maximum integer that a variable can hold. Actually one of my variable holds value 2231599773 and hence the script fails to process it.Do we have any other data type or options available to handle this long integers? (9 Replies)
I read 3 variables from from Inputfile.txt the third one "startnumber" is a number when i compare it with 9 ($startnumber -le 9) it give's me a "unary operator expected", i know that -le is for number comparison. What i need is to convert $startnumber to integer (i have try to do it with expr but... (8 Replies)
Hi Guys,
i guess there is a several ways to grub the strings from date and time
like THISMONTH='/bin/date +%m'
but the hard part is to add or sub that string to a variable
i tried to use let command
TWOMONTHSAGO=$THISMONTH
declare -i TWOMONTHSAGO
let TWOMONTHSAGO-=2
but there... (1 Reply)
Hi Folks -
Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64
I have a process that determines the start and end load periods for an Oracle data load process.
The variables used are as follows follows:
They are populated like such:
However, the load requires the month to be the... (11 Replies)
Discussion started by: SIMMS7400
11 Replies
LEARN ABOUT PLAN9
tail
TAIL(1) General Commands Manual TAIL(1)NAME
tail - deliver the last part of a file
SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ]
tail [ -fr ] [ -n nlines ] [ -c ncharacters ] [ file ]
DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied.
Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K
blocks or characters, according to the appended flag or Default is -10l (ten ell).
The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to
keep watch and print further data as it appears.
The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed.
EXAMPLES
tail file
Print the last 10 lines of a file.
tail +0f file
Print a file, and continue to watch data accumulate as it grows.
sed 10q file
Print the first 10 lines of a file.
SOURCE
/sys/src/cmd/tail.c
BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length.
According to custom, option +number counts lines from 1, and counts blocks and characters from 0.
TAIL(1)