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Operating Systems Solaris How to Use a Variable as Integer? Post 302546375 by shatztal on Thursday 11th of August 2011 05:13:03 AM
Old 08-11-2011
How to Use a Variable as Integer?

hello,
i am writing a script that takes the UID from the PASSWD and then i want
to increse the Number by one. for the Next user.
i cannot get this to work that a variable is as interger
example:
Code:
set i = 0
set $i = $+1

it's in tcsh if it's mather

Last edited by fpmurphy; 08-11-2011 at 09:44 AM..
 

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SLAPD-PASSWD(5) 						File Formats Manual						   SLAPD-PASSWD(5)

NAME
slapd-passwd - /etc/passwd backend to slapd SYNOPSIS
/etc/ldap/slapd.conf DESCRIPTION
The PASSWD backend to slapd(8) serves up the user account information listed in the system passwd(5) file. This backend is provided for demonstration purposes only. The DN of each entry is "uid=<username>,<suffix>". Note that non-base searches scan the the entire passwd file, and are best suited for hosts with small passwd files. CONFIGURATION
This slapd.conf option applies to the PASSWD backend database. That is, it must follow a "database passwd" line and come before any subse- quent "backend" or "database" lines. Other database options are described in the slapd.conf(5) manual page. file <filename> Specifies an alternate passwd file to use. The default is /etc/passwd. ACCESS CONTROL
The passwd backend does not honor any of the access control semantics described in slapd.access(5). Only read (=r) access to the entry pseudo-attribute and to the other attribute values of the entries returned by the search operation is honored, which is performed by the frontend. FILES
/etc/ldap/slapd.conf default slapd configuration file /etc/passwd user account information SEE ALSO
slapd.conf(5), slapd(8), passwd(5). OpenLDAP 2012/04/23 SLAPD-PASSWD(5)
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