08-10-2011
One way that should work is "sed".
However, not sure about the syntax.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I need to sort a file, the sort is not a alphabetical sort, it's based on a predefined order which is read from a file called fSortOrder.
The format of the fSortOrder file is :
STARTPATH"
....
....
The file that needs to be sorted is called tmpUnsorted and contains data in the format : ... (6 Replies)
Discussion started by: Vashj
6 Replies
2. UNIX Desktop Questions & Answers
Hi there
I need to grep for a detail from a file. The pattern to search for involves escape sequences in it. This causes for the problem.
grep "P\_SOME\_STRING\_SEARCH" filename
Note, I have line like below in the file and expect it to grep.
select *
from my_system_param
... (3 Replies)
Discussion started by: guruparan18
3 Replies
3. Shell Programming and Scripting
I have a file that I am processing with a while loop from, in come cases the grep/sed command (strings record | grep “errorDetail” | sed 's&*errorDetail\(.*)\(/errorDetail\).*&\1&') works and produces the data I am after and in some it does not. I have inspected the data within the failing... (3 Replies)
Discussion started by: gugs
3 Replies
4. UNIX for Advanced & Expert Users
All,
I am trying to grep "-----" from a test when i use this i am getting the below error. What is the reason for this ?????... How can i over come this
##) echo "----------------- test_sys_job -----------------" | grep "-----------------"
grep: illegal option -- -
grep: illegal... (6 Replies)
Discussion started by: arunkumar_mca
6 Replies
5. UNIX for Dummies Questions & Answers
Hi folks
I am issuing the following command:
grep "" *
Looking for the characters \/:*?"<>|#+%& within all files in a directory, but the command fails being unhappy with pipe:
ksh: 0403-057 Syntax error: `|' is not expected.
How do I force the command to take the pipe | ? I guess... (2 Replies)
Discussion started by: daveaasmith
2 Replies
6. Shell Programming and Scripting
hi,
i search a command to get follow solution:
file:
21082009mueller01testtest
22082009mueller02testtest
23082009mueller03testtest
24082009mueller02testtest
25082009mueller03testtest
Solution:
I search all lines with "mueller02" at the range 8 to 17
It is possible with
greb... (5 Replies)
Discussion started by: Timmää
5 Replies
7. Shell Programming and Scripting
Need Help For GREP
I have a file say g1.txt and content of file is below
REG ADD "HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\Explorer" /v NoDrives /t REG_DWORD /d 4 /f ,
REG ADD "HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\Explorer" /v NoClose /t REG_DWORD /d 1 /f ,... (4 Replies)
Discussion started by: jalpasoni
4 Replies
8. Shell Programming and Scripting
Hi,
I have a file which has numerous lines and some of the lines having special characters in it. i want to grep the lines which are having special characters.
say,
one line looks like - %*()$#@"", | acbd
antoher line looks like ***##^%! | efcg
so these kind of lines are present... (5 Replies)
Discussion started by: rbalaj16
5 Replies
9. Shell Programming and Scripting
a='CASH$$A'
/usr/xpg4/bin/grep -F "$a" *.txt
It is not able to grep CASH$$A string as it contains special character $$.
I also tried with
/usr/xpg4/bin/grep -F '$a' *.txt
but still not working.
I have to assign CASH$$A to a variable and serach that variable..i dont want to search the... (8 Replies)
Discussion started by: millan
8 Replies
10. Shell Programming and Scripting
Hi,
This code works for me for file in $(find /path/to/dir -type f); do tr -d '\r' <$file >temp.$$ && mv temp.$$ $file done
However, i want this code to skip all .class files.
Can you help me with the modified code. (2 Replies)
Discussion started by: mohtashims
2 Replies
LEARN ABOUT LINUX
shtool-subst
SHTOOL-SUBST.TMP(1) GNU Portable Shell Tool SHTOOL-SUBST.TMP(1)
NAME
shtool-subst - GNU shtool sed(1) substitution operations
SYNOPSIS
shtool subst [-v|--verbose] [-t|--trace] [-n|--nop] [-w|--warning] [-q|--quiet] [-s|--stealth] [-i|--interactive] [-b|--backup ext]
[-e|--exec cmd] [-f|--file cmd-file] [file] [file ...]
DESCRIPTION
This command applies one or more sed(1) substitution operations to stdin or any number of files.
OPTIONS
The following command line options are available.
-v, --verbose
Display some processing information.
-t, --trace
Enable the output of the essential shell commands which are executed.
-n, --nop
No operation mode. Actual execution of the essential shell commands which would be executed is suppressed.
-w, --warning
Show warning on substitution operation resulting in no content change on every file. The default is to show a warning on substitution
operations resulted in no content change on all files.
-q, --quiet
Suppress warning on substitution operation resulting in no content change.
-s, --stealth
Stealth operation. Preserve timestamp on file.
-i, --interactive
Enter interactive mode where the user has to approve each operation.
-b, --backup ext
Preserve backup of original file using file name extension ext. Default is to overwrite the original file.
-e, --exec cmd
Specify sed(1) command directly.
-f, --file cmd-file
Read sed(1) command from file.
EXAMPLE
# shell script
shtool subst -i -e 's;(c) ([0-9]*)-2000;(c) 1-2001;' *.[ch]
# RPM spec-file
%install
shtool subst -v -n
-e 's;^(prefix=).*;1 $RPM_BUILD_ROOT%{_prefix};g'
-e 's;^(sysconfdir=).*;1 $RPM_BUILD_ROOT%{_prefix}/etc;g'
`find . -name Makefile -print`
make install
HISTORY
The GNU shtool subst command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 2001 for GNU shtool. It was prompted
by the need to have a uniform and convenient patching frontend to sed(1) operations in the OpenPKG package specifications.
SEE ALSO
shtool(1), sed(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-SUBST.TMP(1)