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Top Forums Shell Programming and Scripting using awk for setting variable but change the output of this variable within awk Post 302545979 by Cowardly on Wednesday 10th of August 2011 05:50:46 AM
Old 08-10-2011
using awk for setting variable but change the output of this variable within awk

Hi all,

Hope someone can help me out here.
I have this BASH script (see below)

My problem lies with the variable path.
The output of the command find will give me several fields. The 9th field is the path. I want to captured that and the I want to filter this to a specific level.

The output of the path is somewhat like this: /Volume/Server/department/otherlevels/....

The part I want to capture in the variable is the department.
I can do this in a single line with awk -F/ '{print $5}' But I need it in an array.

Using it like it is now will give me an error.

Any idea how to resolve this ?

Many regards,

Ronald



Code:
find . -iname $1 -exec ls -l {} \; | awk 'BEGIN {

# Initialize all Arrays
        size = "0";
        u_count[""]=0;
        all_count[""]=0;
}
{
# Assign field names
        sizes=$5
        path=$( echo $9 awk {-F/ '{print $5}'} )


Last edited by Scott; 08-10-2011 at 07:10 AM.. Reason: Please use code tags for code
 

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SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME
shtool-path - GNU shtool command dealing with shell path variables SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...] DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found. OPTIONS
The following command line options are available. -s, --suppress Supress output. Useful to only test whether a program exists with the help of the return code. -r, --reverse Transform a forward path to a subdirectory into a reverse path. -d, --dirname Output the directory name of str. -b, --basename Output the base name of str. -m, --magic Enable advanced magic search for ""perl"" and ""cpp"". -p, --path path Search in path. Default is to search in $PATH. EXAMPLE
# shell script awk=`shtool path -p "${PATH}:." gawk nawk awk` perl=`shtool path -m perl` cpp=`shtool path -m cpp` revpath=`shtool path -r path/to/subdir` HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken over into GNU shtool. SEE ALSO
shtool(1), which(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)
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