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Full Discussion: help in script needed
Top Forums UNIX for Dummies Questions & Answers help in script needed Post 302545867 by agama on Tuesday 9th of August 2011 10:00:35 PM
Old 08-09-2011
It is quite possible that the output from your dsjob command contains tab characters rather than spaces, and that would cause grep not to find your strings.

Try this as your grep expression:

Code:
"Job.*Status.*RUN.*FAILED"

That should search for the enough of the desired words, in order, without regard to intermediate whitespace (tabs or spaces) or special characters like the colon.

Unfortunately the date command is very inconsistent from version to version of *NIX. To that end, provided your awk supports the systime() and strftime() functions, this is probably the easiest way to get 'yesterday' in the string format that you want. It computes the current time, subtracts a day (86400 seconds) and finally formats it. The string is put into the shell variable "yesterday" which you can use on a grep command:
Code:
yesterday=$( awk 'BEGIN{ str=strftime( "%a %b %d", systime()-86400 ); print str; }')

Given that, use egrep to match both lines, and test the number of matched lines rather than the return code to determine if there was a "hit."

Code:
count=$(dsjob ---your parameters--- | egrep -c  "$yesterday|Job.*Status.*RUN.*FAILED")
if (( $count == 2 ))   
then
   echo "this job failed yesterday"
else
   echo "this job was successful, OR didn't run yesterday"
fi


Last edited by agama; 08-09-2011 at 11:14 PM.. Reason: fixed egrep
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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