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Top Forums Shell Programming and Scripting jobs command behaving differently in script Post 302545454 by nealh on Monday 8th of August 2011 11:22:40 AM
Old 08-08-2011
jobs command behaving differently in script

Here is my test script:
Code:
#!/bin/sh
result=`jobs`
echo "
Jobs:
"$result

result=`ls`
echo "
LS
"$result

Here is the output:

Jobs:


LS
0 1 2 3 4 5 6 7 gcd initialize.sh #inter_round_clean.sh# inter_round_clean.sh inter_round_clean.sh~ look parallel_first_run.sh parallel_ith_run.sh README.txt test testscript.sh testscript.sh~

But when I enter "jobs" from the command line I get this:
[2] Running emacs inter_round_clean.sh &
[3]- Running emacs ../todo.txt &
[5]+ Running emacs testscript.sh &

Why isn't jobs behaving the same was as ls?

p.s. I tried the exact same thing but with $() instead of backticks and got the same result.
 

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INFO(1)                                                            User Commands                                                           INFO(1)

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Email bug reports to bug-texinfo@gnu.org, general questions and discussion to help-texinfo@gnu.org. Texinfo home page: http://www.gnu.org/software/texinfo/ COPYRIGHT
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The full documentation for info is provided by the texinfo-doc-nonfree package as a Texinfo manual. If this package is installed at your site, the command info info should give you access to the complete manual. (Or, if you have Emacs, M-x info will lead to the manual.) info 6.5 February 2018 INFO(1)
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