Job Status : RUN OK (1)
Job Controller : not available
Job Start Time : Mon Feb 21 00:04:09 2011
Job Wave Number : 1
User Status : not available
Job Control : 0
Interim Status : NOT RUNNING (99)
Invocation ID : not available
Last Run Time : Mon Feb 21 00:04:11 2011
Job Process ID : 0
Invocation List : job123
Status code = 0
So, while executing the below code:
Code:
dsjob -server servname -user uname -password pwd -jobinfo Prjname job123
|grep "Job Status : RUN FAILED (3)"
t should return non zero return code since it doesn't contain the search string.
so $? gives 1.
At the same time, the below code also returns 1(even though the search term is found).
Code:
dsjob -server servname -user uname -password pwd -jobinfo Prjname job123
|grep "Job Status : RUN OK (1)"
Can any one help me on this?
Thanks
Moderator's Comments:
Please use [CODE] tags () instead of [QUOTE] tags () when posting command lines, terminal output, ...
---------- Post updated at 01:25 PM ---------- Previous update was at 11:25 AM ----------
From the output:
Code:
Job Status : RUN OK (1)
Job Controller : not available
Job Start Time : Sun Aug 07 00:04:09 2011
Job Wave Number : 1
User Status : not available
Job Control : 0
Interim Status : NOT RUNNING (99)
Invocation ID : not available
Last Run Time : Sun Aug 07 00:04:11 2011
Job Process ID : 0
Invocation List : job123
Status code = 0
I need to search for the strings "Job Status : RUN OK (1)" and " Last Run Time : Sun Aug 07"(sysdate-1).
May i know how to do this in grep?
Thanks
---------- Post updated at 06:37 PM ---------- Previous update was at 01:25 PM ----------
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