Find, regular expression, anyway to simplify this find command?
Hello everyone,
first post here, trying to learn scripting on my own and this forum as been really helpful so far. I made few little scripts working great but I m facing some problems with RE.
I have a bunch of files in many subdirectories called *001.ext *002.ext OR simple *.ext or *01.ext *02.ext And I want to use the find command to only show files *.ext or *01.ext or *001.ext without showing *101.ext *98.ext etc
So the output I want should only show files named like this :
Is there anyway to simplify this? I m not used to regular expressions but I m sure there must be a cleaner, simpler command for this. I tried to find answers on different websites about how regular expressions work but in this case it's giving me a headache
For now I m using this command to process my result through "find -exec" it works great but kinda restrictive. Idealy when I ll manage to, I ll export the result from find in a file (find blabla > test.txt) and then make a loop processing each line from test.txt and assign different variables to line 1, then execute a specific command and then process line 2 until there is no more lines to process.
But right now I just want to simplify this find command if anyone got better idea?
Hi,
I want to find the files available in a directory /var/user/*/*/data/.
I tried using the command "find /var/user/ -path '*/*/data/ -name '*' -type f" it says find: 0652-017 -path is not a valid option and then i tried using "find /var/user/ -name '*/*/data/*' -type f" but its not... (3 Replies)
I suspect this is commonly done, but haven't found the right combination of search terms to find the answer.
I want to grep for lines in .cpp files that contain only 1 '=' sign in an if statement. e.g.,
if (a = b) -- find this
if (a==b) -- don't find this
My attempt:
egrep... (7 Replies)
I'm trying to math all class references in a C++ file using grep with regular expression. I'm trying to know if a specific include is usuless or not, so I have to know if there is a refence in cpp.
I wrote this RE that searches for a reference from class ABCZ, but unfortunately it isn't working... (0 Replies)
Hi,
in the cobol copy books is there any regular expressions to be used in awk to fetch the length of each columns?
below mentioned are the examples.
Copy Book Sample
01 tablename.
02 group header.
03 col1 s9(10)V99.
03 Col2 s9(10)V9(3).
03 Col3 XXXX
02... (7 Replies)
Hi, I would like to use find command to find file with a predefined extension
for example find . modules/*.ksh *.lib
I thought it's possible to use something like :
find . modules/*. but it does not work. is there any other way?
Thanks you (2 Replies)
Hello,
I am trying to use regex wtih find command in KSH. For some reason it is not working as expected.
Input:
comm_000_abc_0102.c
comm_000_abc.c
456_000_abc_1212.cpp
456_000_abc_.cpp
Expected Output:
comm_000_abc_0102.c
kkm_000_abc_8888.cpp
(Basically I want to find all... (6 Replies)
Hi all
I have a list of file names in array. But this file names are not exact. so i want to search whether a file exists or not using regular expression.
code snippet:
if ;
then
echo "File exists"
else
echo "File does not exits"
fi
over here "*EQST*" should be treated as a regular... (4 Replies)
Hello all,
I need to print directories using find command. The directories names contain date in the format YYYYMMDD or the name of directory is only the date format. I want print directories, which doesn't start with this date.
E.g I have dirs like
foo20120101
foo20120101foo
20120101foo... (1 Reply)
Hi Gurus,
I need to identify the file with below format:
ABC20110101.DAT
ABCD2011010103.DAT
If I use ABC*\.DAT, it get two file. I want to get file after "ABC' then number, the ".DAT".
I tried
ABC* but it doesn't work.
Thanks in advance. (9 Replies)
I have files:
sum_<INPUT FILENAME>.YYYYMMDDhhmmss.csv
and
sum_details_<INPUT FILENAME>.YYYYMMDDhhmmss.csv
I have no idea, what is input filename, but in the code I would like to catch them in case
I process them in the loop above case statement
for *.${Today}.*.txt... (3 Replies)
Discussion started by: digioleg54
3 Replies
LEARN ABOUT DEBIAN
file::find::rule::procedural
File::Find::Rule::Procedural(3pm) User Contributed Perl Documentation File::Find::Rule::Procedural(3pm)NAME
File::Find::Rule::Procedural - File::Find::Rule's procedural interface
SYNOPSIS
use File::Find::Rule;
# find all .pm files, procedurally
my @files = find(file => name => '*.pm', in => @INC);
DESCRIPTION
In addition to the regular object-oriented interface, File::Find::Rule provides two subroutines for you to use.
"find( @clauses )"
"rule( @clauses )"
"find" and "rule" can be used to invoke any methods available to the OO version. "rule" is a synonym for "find"
Passing more than one value to a clause is done with an anonymous array:
my $finder = find( name => [ '*.mp3', '*.ogg' ] );
"find" and "rule" both return a File::Find::Rule instance, unless one of the arguments is "in", in which case it returns a list of things
that match the rule.
my @files = find( name => [ '*.mp3', '*.ogg' ], in => $ENV{HOME} );
Please note that "in" will be the last clause evaluated, and so this code will search for mp3s regardless of size.
my @files = find( name => '*.mp3', in => $ENV{HOME}, size => '<2k' );
^
|
Clause processing stopped here ------/
It is also possible to invert a single rule by prefixing it with "!" like so:
# large files that aren't videos
my @files = find( file =>
'!name' => [ '*.avi', '*.mov' ],
size => '>20M',
in => $ENV{HOME} );
AUTHOR
Richard Clamp <richardc@unixbeard.net>
COPYRIGHT
Copyright (C) 2003 Richard Clamp. All Rights Reserved.
This module is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
SEE ALSO
File::Find::Rule
perl v5.12.4 2011-09-19 File::Find::Rule::Procedural(3pm)
08-06-2011
Find, regular expression, anyway to simplify this find command?
