Hi all,
I have a shell script(ksh) which has the code as follows.
------------------
cd $mydir
for i in `find ./ -type f -mtime +$k`
do
echo $i
done
-----------------------
And in $mydir , i have some files which have space in theie names like "Case att15".
The out put of the... (6 Replies)
Can you please tell me how to find a file in a directory and then if it exists i need to place it in a different folder?
I have to use "ls -lt" command
I mean this command is something existing one . can you please tell me how i set the directory path. Like
dir1/dir2/filename.csv to... (8 Replies)
Is there a way to move the files ALONE from one dir to another dir?
In my source dir,I have files as well as directories.I want to move the files alone to another dir and the directories should remain undisturbed.
If I use mv * < target dir> ,then the directories also moved.
Any... (4 Replies)
Hi,
I have a requirement where
I need to move Bunch of folders containing multiple files to another archive location.
i want to use mv command .I am thinking when we use mv command to move directory does it create directory 1st and then move all the files ?
e.g
source... (4 Replies)
I am currently using below command to get the 1st three characters of a file(PDM). Issue is, when i use find command in root dir, it finds all the files in sub dir also.
How to limit the find command search to a given path only(ie: say only find file in apps/cmplus/datamigration/data path... (3 Replies)
Hi All,
I'm a bit new to Linux environment, moderately okay when it comes to Unix AIX. I'm facing an issue while trying to run a simple find command:
$ for file in `find . -name *.*`
> do
> ls $file
> done
This is throwing the following error:
Strangely, a few minutes... (4 Replies)
Hi Friends,
I'm facinf issue while moving large files using find command.I've a scenario like i've to move one day older files from one directory to anothe directory.I'm using the below command.
find $src_dir -name error -prune -o -type f -mtime +1 -exec mv {} $dest_dir \;
some times... (1 Reply)
Guys,
Here is my requirement..
Sample.cfg
file="*log.gz *txt.gz"
sample.sh
#!/bin/sh
. $HOME/Sample.cfg
find . -name "$file" -mtime +20 -exec ls -la {} \;
Its not finding the given *log.gz and txt.gz files.
Could anyone please help me? (8 Replies)
Hi
I am using the below code to find mv the files.
Files are moving to the Target location as expected but find is displaying some errors like below.
find ./ -name "Archive*" -mtime +300 -exec mv {} /mnt/X/ARC/ \;
find: `./Archive_09-30-12': No such file or directory
find:... (6 Replies)
Hi Guys,
I have a file called error.logs. am just trying to display the content in the file which was modified last 1 day. I tried below command but it doesnt give the proper output.
find /u/text/vinoth/bin "error.logs" -mtime -1 -exec cat {} \; >> mail.txt
Any help is much... (21 Replies)
Discussion started by: Vinoth Kumar G
21 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)