07-26-2011
Methinks that running the unix commands "pwck" and "grpck" before you start would be wise.
Quote:
so to remove the user from group2, issue the command:
Code:
# usermod -G group1,group3 user1
This command is incorrect. The "-G" defines the primary group. A user cannot have more than one primary group. This is academic anyway because the user has been removed "manually" from /etc/passwd and /etc/shadow therefore cannot be referred to by name (hence the error message).
Where relevant to your Operating System be sure that the "pwconv" command was run after a manual edit to /etc/passwd (which used "vipw" not "vi" we hope).
As no command now can refer to the deleted users by name the only possible repair is to use an editor to repair the Group file.
Obviously copy the /etc/group file before editing the file and use the unix command "grpck" before and after to check the Group file for inconsistencies.
Last edited by methyl; 07-26-2011 at 08:34 PM..
Reason: assorted typos and additions
10 More Discussions You Might Find Interesting
1. Solaris
I want to know the command line to removed the only secondary group existed from a user on an HP/SUN. :confused: (1 Reply)
Discussion started by: jquizon62
1 Replies
2. UNIX for Advanced & Expert Users
I'm kinda new to unix programming so bear with me...
I'm running a script prompting a user for an existing user and group and want to be able to validate if they valid.
Is there any code available?
Any help or push in the right direction would help.
Thank you, (2 Replies)
Discussion started by: thedon
2 Replies
3. Red Hat
im trying to get an ARP readout using the command 'arp -a'... but the command doesnt exist in Fedora Core 6 - IPv6.... is there an equivalent command? (4 Replies)
Discussion started by: HMSS013
4 Replies
4. Shell Programming and Scripting
Hi,
Another problem, here is my code
#!/bin/sh
dir='/opt/apps/script/CSV'
datadir='/opt/apps/script/data'
while : ; do
ls -1rt $dir/*.csv > /dev/null 2>&1
if ;then
cp $datadir/weekly.txt $dir/weekly.csv
else
exit 0
fi
done (10 Replies)
Discussion started by: tententen
10 Replies
5. Shell Programming and Scripting
I tried a few ways to resolve this using a bash script w/ a loop, no luck.
File1: roughly 6,000 account numbers such as:
1111
1512
1113
123
I also have a dozen or so csv files, w/ the account number in the 4th field. What I would like to do is remove all lines if the... (19 Replies)
Discussion started by: svn
19 Replies
6. Shell Programming and Scripting
Hey People,
I've got a question! How can i write a function in a script which is looking for if a group exist and if not, that the group "users" is the standard group..I know that i have to use "grep" und "if-else"..I will be very happy for answers ;)
Greetz
Ali (2 Replies)
Discussion started by: AliC
2 Replies
7. Shell Programming and Scripting
I am trying to add some code to the begging of a script so that it will remove all the .transcript files, when their is no coressponding .wav file. But it doesnt work.
This is the code I have added:
for transcriptfile in `$voicemaildir/*.transcript`; do
wavfile=`echo $transcriptfile | cut -d'.'... (2 Replies)
Discussion started by: ghurty
2 Replies
8. Red Hat
Our SAN administrator decided to unpresent then destroy LUN's we were actively using as a volume group (all PV's in said volume group). Now every time I do a pvscan or whatever it complains about I/O errors trying to access those PV's. How do I get it to forget the VG existed completely? vgreduce... (7 Replies)
Discussion started by: thmnetwork
7 Replies
9. Red Hat
Hi,
In the following output you can see the the user "richard" is a member on the team/group "developers":
# id richard
uid=10247(richard) gid=100361(developers) groups=100361(developers),10053(testers)
but in the following details of the said group (developers), the said user... (3 Replies)
Discussion started by: indiansoil
3 Replies
10. Homework & Coursework Questions
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
I'm able to create a group but when I'm trying to delete the group it keeps stating Group Doesn't Exist. I know... (2 Replies)
Discussion started by: GoBoyGo
2 Replies
pwck(1M) System Administration Commands pwck(1M)
NAME
pwck, grpck - password/group file checkers
SYNOPSIS
/usr/sbin/pwck [filename]
/usr/sbin/grpck [filename]
DESCRIPTION
pwck scans the password file and notes any inconsistencies. The checks include validation of the number of fields, login name, user ID,
group ID, and whether the login directory and the program-to-use-as-shell exist. The default password file is /etc/passwd.
grpck verifies all entries in the group file. This verification includes a check of the number of fields, group name, group ID, whether any
login names belong to more than NGROUPS_MAX groups, and that all login names appear in the password file. The default group file is
/etc/group.
All messages regarding inconsistent entries are placed on the stderr stream.
FILES
/etc/group
/etc/passwd
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO
getpwent(3C), group(4), passwd(4), attributes(5)
DIAGNOSTICS
Group entries in /etc/group with no login names are flagged.
Group file 'filename' is empty
The /etc/passwd or /etc/group file is an empty file.
cannot open file filename: No such file or directory
The /etc/passwd or /etc/group file does not exist.
NOTES
If no filename argument is given, grpck checks the local group file, /etc/group, and also makes sure that all login names encountered in
the checked group file are known to the system getpwent(3C) routine. This means that the login names may be supplied by a network name
service.
SunOS 5.10 20 Oct 2002 pwck(1M)