@aLHaNz c1 variable is holding a numeric value after all
the following code fragment
in simple speaking it says extract the lines that contains the value stored in the variable $title as a word then refine this extracted lines with another filter against the value stored in the variable $author then pass the out to some sort of line counter that what it says in final $c1 will hold a numeric value if conditions of combined filters are met.
I see no logical errors in the function
.
Also I see no string comparison in the snippet you sent except the pattern matching logic
Hi
How do i compare two strings in shell script. Below is an example but I am not getting the desired output, plz help
if
then
echo success
fi
I am not getting the desired output if I do this. plz help (24 Replies)
Hi All,
While I am trying to run below code I Am getting the exception like
./abs.sh: line 102: syntax error near unexpected token `then'
./abs.sh: line 102: ` then'
The Code Snippet is:
if then
cat $file1 | sed -e... (8 Replies)
i have a string in a file which gets repeated number of times like below:
rpttxt("abc")
.
.
rpttxt("REP_TITLE")
rpttxt("BOS_TITLE")
.
.
.
.
and so on
using awk or grep how can i comapre the string( as the second half keeps varying) and store it in a temporary variable? I am using the... (3 Replies)
hi All
i am facing prob in comparing two strings that have two word.
below is the code snippet.
checkValidates="file validates"
file3_name="file"
if
then
echo "file" $file3_name "is validated successfully"
fi
when i run this i get the error as -bash: [: too many arguments
... (1 Reply)
Hello All
Please I have got a file called DATE.tex which consist of
01-04-2008_12:00:00
01-04-2005_12:00:00
01-04-2003_12:00:00
01-04-2007_12:00:00
01-04-2002_12:00:00
01-04-2009_12:00:00
I want to use nawk to print out the dates >=01-04-2009_12:00:00
I tried this
cat plnt.new |... (6 Replies)
Hi, So I got his code below. $year is a string of 2010,2011 etc.
I guess I want to convert $year to an integer so I can do my if statement to see if the year string is greater than 2010? Or how could I do this?
Right now I get a syntax error doing this.
if; then
do stuff
fi (2 Replies)
Hi I tried the following string comparison script in Ksh88
#!/bin/ksh
str1='aC'
str2='ABC'
if
then
echo "Equal"
else
echo "Not Equal"
fi
Though str1 and str2 are not equal the script output says Equal .
Please correct me
Thanks (2 Replies)
Discussion started by: smile689
2 Replies
LEARN ABOUT POSIX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)