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Full Discussion: grep on string and printing line after until another string has been found
Top Forums Shell Programming and Scripting grep on string and printing line after until another string has been found Post 302541257 by rxc23816 on Saturday 23rd of July 2011 10:59:22 AM
Old 07-23-2011
Quote:
Originally Posted by bartus11
For your sample data this should work:
Code:
awk -vact="$ACTNUMBER" '$0~"START.*ACTNUMBER="act,/FINISH/' logfile

As for the nested START/FINISH, please post example of such case and the desired output.
Thanks..
There are multiple instances of START to FINISH with the ACTNUMBER within. This script needs to display all of those instances.

However some have another START and FINISH within the START and FINISH.

So sometimes, it will look like this
xxxxxx START xxxxxxxxxxxxxxxx ACTNUMBER=1234 xxxxxxxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxx FINISH xxxxxxxxxxxxxxxxxxxxxxxxxx

and sometimes there will be this.....

xxxxxx START xxxxxxxxx START xxxxxxxx ACTNUMBER=1234 xxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx FINISHxxxxxxxxxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxxxxx FINISH xxxxxxxxxxxxxxxxxxxxxxxxxxxxx

This is a long log file so there will be multiple instances of these log snippets then I need the script to display to output in a numbered format with a carriage return between each instance

Someone mentioned grep and using a counter to look for the first and second instance of START and the first and second instance of FINISH if there is one.

Basically what I'm looking for is
for it to find START , if theres a start look for the ACTNUMBER
print or echo that particular line
Look for the same on next line. if this is false, still print the line
Look for the same on next line. if this is false, still print the line
Look for FINISH. If this is true, print the line, then I need it to loop recursively.

For the past week I've been in the grep state of mind. I guess I was way off lol

grep -n START | grep -n ACTNUMBER=$ACTNUMBER gets me the START and ACTNUMBER but I just couldn't figure out how to get those lines to print until FINISH

---------- Post updated at 10:59 AM ---------- Previous update was at 10:57 AM ----------

Quote:
Originally Posted by fpmurphy
grep is not really a good tool to use for this kind of thing. I suggest you look at either awk, perl or sed.

For example, here is one way of printing all lines between START/ACTNUMBER and FINISH using sed:
Code:
sed -n '/START:\(.*\)ACTNUMBER/,/FINISH:/p' file

It does not handle the nested case. For that you need to use a tool like awk or perl.
Thanks.. what does the (.*\) mean? Does that mean everything between START and ACTNUMBER?
 

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