For a programming exercise, I am mean to design a Perl script that detects double letters in a text file.
I tried the following expressions
# Check for any double letter within the alphabet
/+/
# Check for any repetition of an alphanumeric character
/\w+/
Im aware that the... (8 Replies)
Hi,
Can anyone help me to find regular expression for the following in Perl?
"The string can only contain lower case letters (a-z) and no more than one of any letter."
For example: "table" is accepted, whether "dude" is not.
I have coded like this:
$str = "table";
if ($str =~ m/\b()\b/) {... (4 Replies)
I have got numbers like
l255677
l376039
l188144
l340482
l440700
l254113
to match the numbers starting with '13' what would be the regex
=~/13(.*)/ =======>This is not working ....
But for user123,user657
regex =~/user(.*)/ ========>works
Thanks for help..!! (7 Replies)
I am having trouble parsing rpm filenames in a shell script.. I found a snippet of perl code that will perform the task but I really don't have time to rewrite the entire script in perl. I cannot for the life of me convert this code into something sed-friendly:
if ($rpm =~ /(*)-(*)-(*)\.(.*)/)... (1 Reply)
HI,
I'm new to perl and need simple regex for reading a file using my perl script.
The text file reads as -
filename=/pot/uio/current/myremificates.txt
certificates=/pot/uio/current/userdir/conf/user/gamma/settings/security/... (3 Replies)
Hi Guys
I have the following regex
$OSRELEASE = $1 if ($output =~ /(Mac OS X (Server )?10.\d)/);
output is currently
Mac OS X 10.7.5
when the introduction of Mac 10.8 output changes to
OS X 10.8.2
they have dropped the Mac bit so i changed the regex to be (2 Replies)
Hello,
I'm trying to get a quick help on regex since i'm not a regular programmer.
Below is the line i'm trying to apply my regex to..i want to use the regex in a for loop and this line will keep on changing.
subject=... (4 Replies)
Could anyone please make me understand how the ?= works below ..
After executing this I am getting the same output.
$string="I love chocolate.";
$string =~ s/chocolate(?= ice)/vanilla/;
print "$string\n"; (2 Replies)
I am not a big expert in regex and have just little understanding of that language.
Could you help me to understand the regular Perl expression:
^(?!if\b|else\b|while\b|)(?:+?\s+){1,6}(+\s*)\(*\) *?(?:^*;?+){0,10}\{
------
This is regex to select functions from a C/C++ source and defined in... (2 Replies)
Experts -
I found a script on one of the servers that I work on and I need help understanding
one of the lines.
I know what the script does, but I'm having a hard time understanding the grouping.
Can someone help me with this?
Here's the script...
#!/usr/bin/perl
use strict;
use... (2 Replies)
Discussion started by: timj123
2 Replies
LEARN ABOUT OPENDARWIN
log2
LOG(3) BSD Library Functions Manual LOG(3)NAME
log, log2, log10, log1p, -- logarithm functions
SYNOPSIS
#include <math.h>
double
log(double x);
double
log2(double x);
double
log10(double x);
double
log1p(double x);
DESCRIPTION
The log() function computes the value of the natural logarithm of argument x.
The log2() function computes the value of the logarithm of argument x to base 2.
The log10() function computes the value of the logarithm of argument x to base 10.
The log1p() function computes the value of log(1+x) accurately even for very small values of x.
SPECIAL VALUES
log(+-0) , log2(+-0) , and log10(+-0) return -infinity and raise the "divide-by-zero" floating-point exception.
log(1) , log2(1) , and log10(1) return +0.
log(x) , log2(x) , and log10(x) return a NaN and raise the "invalid" floating-point exception for x < 0.
log(+infinity) , log2(+infinity) , and log10(+infinity) return +infinity.
log1p(+-0) returns +-0.
log1p(-1) returns -infinity and raises the "divide-by-zero" floating-point exception.
log1p(x) returns a NaN and raises the "invalid" floating-point exception for x < -1.
log1p(+infinity) returns +infinity.
SEE ALSO math(3), exp(3), exp2(3), expm1(3), pow(3), infnan(3)STANDARDS
The log() , log2() , log10() , and log1p() functions conform to ISO/IEC 9899:1999(E).
4th Berkeley Distribution July 2, 2003 4th Berkeley Distribution