Given this XML:
I'm using the following code to determine if the root element is 'catalog' or not.
This works fine for a <catalog> file, but I also need to determine other file types by reading the root element. Does anyone know of a method using XML::LibXML (or similar) module that would return the name of the root element?
Hi All,
I am looking for a awk/shell which can find an element named REFERENCE in a XML file and check whether it is empty or not.
If there is no value in the REFERENCE element then correspondingly move the file to some other folder.
The Unix server is AIX version 4.
Any inputs... (9 Replies)
Hi All
Can someone please help me with this awk to search an element in a XML file with a particular value and then change the root element.
Thanks & Regards
Karan (9 Replies)
I have a rather large file with XML-style content. Each line contains one full XML entry. For example:
1:<Message><DNIS>1234</DNIS><UCID>3456</UCID><TransferGroup>XYZXYZ</TransferGroup></Message>
2:<Message><DNIS>9999</DNIS><UCID>2584</UCID><TransferGroup>ABCABC</TransferGroup></Message>... (1 Reply)
Hi, I would need to read an xml element from an xml file to a local variable. Please could you help me with a shell script to get so? Considering that I have a file called file.xml like below:
<header>
<description>This is the description</description>
<content>This is the... (2 Replies)
hi experts:
i am using xslt to transform xml in shell.
But can not find root node of source xml, if i remove the naming space definition in source xml, it works fine.
So our the question is how to let xslt know the naming space of srouce xml file?
Thanks for your kindly help in... (0 Replies)
Any help to extract the root element from an XML file will be appreciated.
Example: test.xml
<?xml version="1.0" encoding="utf-8" ?>
<TestXMLMessage>
<TestRec>
<ID>1000</ID>
</TestRec>
</TestXMLMessage>
Wanted to extract the TestXMLMessage.
Regards,
Chari (6 Replies)
Hi,
I'm trying to write a script for some xml file handling, but I'm not getting too far with it.
I've got the following xml content
<?xml version="1.0" encoding="UTF-8"?>
<Test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >
<Operation name="OPER1">
<Action name="ACTION1">... (2 Replies)
I want to check if every <Part> element has corresponding <Description> in this sample XML.
....<Lot Of XML>
<Inv lineNumber="2">
<Item>
... (4 Replies)
HI
I am looking for a easy way to merge 2 xml files like the following
file 1: will have a structure like this
<Group GID="TOTO" NAME="TOTO" UNITS="1.0">
<Property NAME="Id" VALUE="TOTO"/>
<Property NAME="Currency" VALUE="USD"/>
<Group... (6 Replies)
XML::LibXML::NodeList::Iterator(3pm) User Contributed Perl Documentation XML::LibXML::NodeList::Iterator(3pm)NAME
XML::LibXML::NodeList::Iterator - Iteration Class for XML::LibXML XPath results
SYNOPSIS
use XML::LibXML;
use XML::LibXML::NodeList::Iterator;
my $doc = XML::LibXML->new->parse_string( $somedata );
my $nodelist = $doc->findnodes( $somexpathquery );
my $iter= XML::LibXML::NodeList::Iterator->new( $nodelist );
# more control on the flow
while ( $iter->nextNode ) {
# do something
}
# operate on the entire tree
$iter->iterate( &operate );
DESCRIPTION
XML::LibXML::NodeList::Iterator is very similar to XML::LibXML::Iterator, but it does not iterate on the tree structure but on a
XML::LibXML::NodeList object. Because XML::LibXML::NodeList is basicly an array the functionality of XML::LibXML::NodeList::Iterator is
more restircted to stepwise foreward and backward than XML::LibXML::Iterator is.
SEE ALSO
XML::LibXML::NodeList, XML::NodeFilter, XML::LibXML::Iterator
AUTHOR
Christian Glahn, <phish@cpan.org>
COPYRIGHT
(c) 2002-2007, Christian Glahn. All rights reserved.
This package is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.10.0 2007-09-28 XML::LibXML::NodeList::Iterator(3pm)