Hi ,
I am trying to find out the List of files modified or added aftter installation of any component on SUN solaris box .
But i am not able to do it using ls or find command .
Can somebody help me out ?
Thanks
Sanjay Gupta (2 Replies)
Hello
I have log file from solaris system which has date field converted by Java application using System.currentTimeMillis() function, example is 1280943608380 which equivalent to GMT: Wed, 04 Aug 2010 17:40:08 GMT.
Now I need a function in shell script which will convert 1280943608380... (3 Replies)
New Unix user/scripter here. Been trying to solve a problem for two days now with no luck. Hoping someone here has an answer.
Essentially I have a list of wtmp files which I have decompressed and copied to a temporary directory. Using the following command I can turn them into a file than can... (4 Replies)
On Solaris 10 server the system date won't match with the timestamp on files created by a cron jobs, Please help
here is what i get when i check for system date
infodba-ie10ux014:/tcpdv1_ie10/tcadmin/bin\n\r-> date
Tue Apr 24 15:27:43 GMT 2012at same time i executed a cron job, and checked... (4 Replies)
Hi All,
I have the following time stamp data in 2 columns
Date TimeStamp(also with milliseconds)
05/23/2012 08:30:11.250
05/23/2012 08:30:15.500
05/23/2012 08:31.15.500
.
.
etc
From this data I need the following output.
0.00( row1-row1 in seconds)
04.25( row2-row1 in... (5 Replies)
Oracle Enterprise Linux
We want to track how long a process takes to complete its execution. This is what we want in the schell script
Before the process is started , get the time with date, hours and minutes
execute the process
After the process has ended , get the time with date,... (5 Replies)
Hello All,
I have two strings with date and time as follows..
$starttime= "06/11/2013 ";
$starttime= "05:15";
$enddate="06/12/2013";
$endtime="04:45";
dates are in mm/dd/yyyy format and time in military format.
and I am looking the duration of time(in minutes) in between dates.
... (3 Replies)
Can someone help me to write a shell script to convert epoch timestamp into human readable format
1394553600,"test","79799776.0","19073982.728571","77547576.0","18835699.285714"
1394553600,"test1","80156064.0","19191275.014286","62475360.000000","14200554.720000"... (10 Replies)
Hi
there is a lot of file dated from last week till ofpresent date.
if i want to list only last 3 days files using ls command how can i do it
please suggest. below is the list of the file.
and i want to list files from MAy 12 to May 16.
Nov 22 2011 NSSM.UPPLSCPLB81
Jan 12... (2 Replies)
I want to calculate duration for below file in this format
SID | Date | Starttime |Date |End time
1607 |2019-04-05|13:06:42|2019-04-05|13:07:12
2327 |2019-04-05|13:57:26|2019-04-05|13:57:43
O/p should be like this:
SID | Date | Starttime |Date |Endtime... (4 Replies)
Discussion started by: anupmishra
4 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)