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Full Discussion: Replacing grep with awk
Top Forums UNIX for Dummies Questions & Answers Replacing grep with awk Post 302539631 by jgrosecl on Monday 18th of July 2011 09:32:57 AM
Old 07-18-2011
Replacing grep with awk
This may be a repetitive or simple question, but I have a long running code, which uses a grep with a big argument, and i was wondering if there was a way to replace all of my greps with awk....here are my two commands using greps.
Code:
x=$(ls /my/directory/here | grep -h ".$variable")

and
Code:
u=$(ls /my/directory/here | grep -E "\.20.{6}\.20")

the second seems to work particularly better than the first. Its purpose is to find all occurrences of .20 .20 with six characters in the middle. I do not think that either statement is very efficient, if an awk statement exist which would better replace these statements, and what these awk statements are.

Thank you.
Last edited by Scott; 07-18-2011 at 10:37 AM.. Reason: Code tags, please...
 

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LEARN ABOUT POSIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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