Hi,
I have a file that has several values seperated by ":"
2006:John:Student:Football:Portugal:Cinema
2006:James:Engineer:Basket:Poland:Theatre
2007:Lucy:Diver:Gymnastic:England:Music
2007:Smith:Plumber:Basket:Spain:Poker
I need make a filter based on the 5th field to find countries that... (1 Reply)
HI,
Your help was great: awk -F":" '$5 ~ /^P/{print }' file
I would like to know what changes need to be done to this line code, so that I can put it in a shell script and call it as the example below.
example: countries that start with chacater 'P'
> country P
Result:
... (0 Replies)
Hi,
I have the following text file:
8 T1mapping_flip02 ok 128 108 30 1 665000-000008-000001.dcm
9 T1mapping_flip05 ok 128 108 30 1 665000-000009-000001.dcm
10 T1mapping_flip10 ok 128 108 30 1 665000-000010-000001.dcm
11 T1mapping_flip15 ok 128 108 30... (2 Replies)
Hi,
I have one file, say file 1, that has data like below where 19900107 is the date,
19900107 12 144 129 0.7380047
19900108 12 168 129 0.3149017
19900109 12 192 129 3.2766666E-02
... (3 Replies)
Hi,
I have two input files as
File1 :
ABC:client1:project1
XYZ:client2-aa:project2
DEF:client4:proj
File2 :
client1:W-170:xx
client2-aa:WT-04:yy
client4:L-005A:zz
Also, array of valid values can be hardcoded like
Output :
ABC:W:project1
XYZ:WT:project2 (1 Reply)
Hi,
I have a tab delimited text file from which I want to cut out specific columns. If the second column equals one, I want to cut out columns 1 and 5 and 6. If the second column equals two, I want to cut out columns 1 and 5 and 7. How do I go about doing that? Thanks! (4 Replies)
Hello,
I have two files as the following:
File1:
F0100020 A G
F0100030 A T
F0100040 A G
File2:
F0100040 A G BTA-28763-no-rs 77.2692
F0100030 A T BTA-29334-no-rs 11.4989
F0100020 A G BTA-29515-no-rs 127.006
I want to sort the second file based on the... (6 Replies)
Suppose i have the following data :
cat file.txt
12431,123334,55353,546646,14342234,4646,35234
123123,3535,123434,132535,1234134,13535,123534
123213,545465,23434,45646,2342345,4656,31243
2355425,2134324,53425,342,35235,23434,234535
3423424,234234,65465,,2344,35436,234524,234... (7 Replies)
I have an xml file dumped from rrd file, that I want to "patch" so the xml file doesn't contain any blank hole in the resulting graph of the rrd file.
Here is the file.
<!-- 2015-10-12 14:00:00 WIB / 1444633200 --> <row><v> 4.0419731265e+07 </v><v> 4.5045912770e+06... (2 Replies)
Discussion started by: rk4k
2 Replies
LEARN ABOUT OSX
svk::log::filter::grep
SVK::Log::Filter::Grep(3) User Contributed Perl Documentation SVK::Log::Filter::Grep(3)SYNOPSIS
SVK::Log::Filter::Grep - search log messages for a given pattern
DESCRIPTION
The Grep filter requires a single Perl pattern (regular expression) as its argument. The pattern is then applied to the svn:log property
of each revision it receives. If the pattern matches, the revision is allowed to continue down the pipeline. If the pattern fails to
match, the pipeline immediately skips to the next revision.
The pattern is applied with the /i modifier (case insensitivity). If you want case-sensitivity or other modifications to the behavior of
your pattern, you must use the "(?imsx-imsx)" extended pattern (see "perldoc perlre" for details). For example, to search for log messages
that match exactly the characters "foo" you might use
svk log --filter "grep (?-i)foo"
However, to search for "foo" without regards for case, one might try
svk log --filter "grep foo"
The result of any capturing parentheses inside the pattern are not available. If demand dictates, the Grep filter could be modified to
place the captured value somewhere in the stash for other filters to access.
If the pattern contains a pipe character ('|'), it must be escaped by preceding it with a '' character. Otherwise, the portion of the
pattern after the pipe character is interpreted as the name of a log filter.
STASH /PROPERTY MODIFICATIONS
Grep leaves all properties and the stash intact.
perl v5.10.0 2008-08-04 SVK::Log::Filter::Grep(3)