QUESTION: How can I cut out the date from just the first line and reformat it to 31-Jul-2007? I'll restate the question at the bottom again...
DESCRIPTION: I need to cut a date out of a file - an example of the date's format in the file is 2007-07-31. It's in the 5th field and is separated... (1 Reply)
Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
Is there a way to use a word as a delimiter with cut? Or is there a way to use sed or awk with a word as a delimiter? I don't care which program I use for a delimiter I just want to use a word as a delimiter. (2 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
Hi,
Can someone help me to get the shortest command
Input file
=========
I|know|"english|french"
It|can|have|four|delimiters
Desired output
===========
"english|french"
have
If I use cut -d "|" -f3 , i am getting "english as 3rd field.But I would like to get the whole text in... (2 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Hi All-
We have a file data as below with delimiter as |#|
10|#|20|#|ABC
13|#|23|#|PBC
If I want to cut the 2nd field out of this, below command is not working as multiple pipe is causing an issue , it seems
cut -f2 -d"|#|" <file_name>
can you please help to provide the correct command... (7 Replies)
Discussion started by: sureshg_sampat
7 Replies
LEARN ABOUT V7
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)