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Top Forums Shell Programming and Scripting ksh/nawk help with if statement to choose between 2 files Post 302537321 by ther2000 on Thursday 7th of July 2011 05:43:34 PM
Old 07-07-2011
I don't think it does..I didn't see anything about it in the man pages and this is the error I got:

Code:
 
 
Jul--%-d
PSP6-SYSG-PC1>>date -d '+3 days' +%b--%-d
date: illegal option -- d
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]
PSP6-SYSG-PC1>>^C
PSP6-SYSG-PC1>>

Thank you though. I actually think I was able to make it work using an if statement:

Code:
 

TODAY1=$(date +"%b-%d" | sed 's/-0/--/')
TODAY2=$(date +"%b-%d")
TODAY_DAY=$(date +"%d")
print $TODAY_DAY
if (($TODAY_DAY < 10))
then
TODAY=$TODAY1
elif (($TODAY_DAY >= 10))
then 
TODAY=$TODAY2
else
print "Error with date computation!"
fi

 

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DATETIME.FORMAT(3)							 1							DATETIME.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTime.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIME.FORMAT(3)
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