I need to replace the line containing "STAGE_DB" with the line
"STAGE_DB $DB # database that contains the table being loaded ($workingDB)"
Here $DB is passed during the runtime.
How can I do this?
Thanks,
Kousikan (2 Replies)
Hi All,
I have almost 1000+ files and I want to search specific pattern. Looking forwarded your input.
Search for: word1.word2 (Which procedure contain this word, I need procedure name in output.
Expected output:
procedure test1
procedure test2
procedure test3
procedure test4
... (7 Replies)
Hi,
I have many scripts in particular directory. And few of the scripts have exit 0 in second line. Now i wanted to list out the scripts name which has the exit 0 in its second line
I tried many options , but i can not get the filename along with the nth line pattern match :mad:. Can anyone... (14 Replies)
I have a pattern
username:x:32005:32006::/usr/local/user:/bin/bash
I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell
So it becomes
username:x:32005:32006::/usr/local/user:/usr/local/my/bin/noshell (7 Replies)
Hi ,
I want to print the nth and n+1 lines from a file once it gets a pattern match.
For eg:
aaa
bbb
ccc
ddd
gh
jjjj
If I find a match for bbb then I need to print bbb as well as 3rd and 4th line from the match.. Please help..Is it possible to get a command using sed :) (6 Replies)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
I need to be able to search for a string in the first column and if that string exists than replace the nth column with "-9.99".
AW12000012012 2.38 1.51 3.01 1.66 0.90 0.91 1.22 0.82 0.57 1.67 2.31 3.63 0.00
AW12000012013 1.52 0.90 1.20 1.34 1.21 0.67 ... (14 Replies)
Im using the command below , but thats not the output that i want. it only prints the odd and even numbers.
awk '{if(NR%2){print $0 > "1"}else{print $0 > "2"}}'
Im hoping for something like this
file1:
Text hi this is just a test
text1 text2 text3 text4 text5 text6
Text hi... (2 Replies)
Hi All,
I have sample of listing as following
Database 2 entry:
Database alias = PXRES
Database name = PXRES
Local database directory = /db2/data1/db2phnx
Database release level = d.00
Comment ... (3 Replies)
Discussion started by: ckwan
3 Replies
LEARN ABOUT DEBIAN
vpl2mod
VPL2MOD.1(1) Sword Module Utilities VPL2MOD.1(1)NAME
vpl2mod - tool to convert verse per line source to SWORD module
SYNOPSIS
vpl2mod SOURCE PATH [0|1] [0|1]
DESCRIPTION
This utility is used to create SWORD module from the verse per line formated source. The resulting module will be saved in the path
specified.
OPTIONS
[0|1] [0|1]
The first option indicates whether to prepend verse references or not. The second option is to indicate whether module is NT only or
not.
NOTE
With no verse references source file must contain exactly 31102 lines. This is KJV verse count plus heading for the module, testament, book
and chapter. An example snippet follows:
MODULE HEADER
OLD TESTAMENT HEADER
GENESIS HEADER
CHAPTER 1 HEADER
In the beginning...
This example implies there must also be a chapter 2 header, Exodus header, New Testament header, etc. If there is no text for the header, a
black line must, at least, hold place.
With verse references, source file must simply contain any number of lines, that begin with the verse reference for which it is an entry,
e.g.:
gen 1:0 CHPATER 1 HEADER
get 1:1 In the beginning...
Authors
This manual page was written by Dmitrijs Ledkovs <dmitrij.ledkov@gmail.com> for Debian project but may be used by others.
SEE ALSO SWORD 1.6.2+dfsg 2012-02-22 VPL2MOD.1(1)