I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi,
I have a csv file with old data..i need to have only last 30 days from the current dateof data in the file.The fourth field in the file is a date field.i need to write a script to delete the old data by comparing the the fourth field with the (current date -30).I need to delete the rows in... (2 Replies)
Hi, as the title states i need to find a way to search a column for values great than 1000, and if it is, then delete that row.
An example
1 7.021 6.967 116.019 4 U 6.980E+07 0.000E+00 e 0 0 0 0
2 8.292 7.908 118.063 3 U 1.440E+07 0.000E+00 e 0 821 814 ... (3 Replies)
Hi Guys,
Anyone who knows how to compare the current date with the a file containing a date, say for example I have a file that looks like this:
Command was launched from partition 0.
------------------------------------------------
Executing command in server server6
Fri Dec 16... (7 Replies)
I want to delete row in csv file , which row value from 2009-10-01 to 2011-06-03 using script.my csv row data look like:
2009-10-01
2011-03-30
2011-03-31
2011-04-01
2011-06-03
2011-06-30
2011-07-01
2011-09-28 ... (7 Replies)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
Code:
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to write a... (3 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT PLAN9
yesterday
YESTERDAY(1) General Commands Manual YESTERDAY(1)NAME
yesterday - print file names from the dump
SYNOPSIS
yesterday [ -c ] [ -date ] files ...
DESCRIPTION
Yesterday prints the names of the files from the most recent dump. Since dumps are done early in the morning, yesterday's files are really
in today's dump. For example, if today is March 17, 1992,
yesterday /adm/users
prints
/n/dump/1992/0317/adm/users
In fact, the implementation is to select the most recent dump in the current year, so the dump selected may not be from today.
With option -c, yesterday copies the dump file to the current directory.
The date option selects other day's dumps, with a format of 2, 4, 6, or 8 digits of the form dd, mmdd, yymmdd, or yyyymmdd.
Yesterday does not guarantee that the string it prints represents an existing file.
EXAMPLES
Back up to yesterday's MIPS binary of vc:
cd /mips/bin
yesterday -c vc
Temporarily back up to March 1's MIPS C library to see if a program runs correctly when loaded with it:
bind `{yesterday -0301 /mips/lib/libc.a} /mips/lib/libc.a
rm v.out
mk
v.out
FILES
/n/dump
SOURCE
/rc/bin/yesterday
SEE ALSO fs(4)BUGS
It's hard to use this command without singing.
YESTERDAY(1)