07-06-2011
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
well, I'm completely stumped so I'm hopeful that someone here may have an answer...one of my development machines is running Solaris 8 and I've been trying to create a folder in /apps. it gives me this message:
mkdir: Failed to make directory "*******"; Operation not applicable
I've tried... (2 Replies)
Discussion started by: jkrotz
2 Replies
2. UNIX for Advanced & Expert Users
Hi all,
I am using Sun Solaris 9 .In this system normal users unable to create files from the command line.I added these users in bin,adm and even root group i found them unable to create a file. (1 Reply)
Discussion started by: mallesh
1 Replies
3. UNIX for Advanced & Expert Users
Version-Release number of selected component (if applicable):
==================================================================
root@server # cat /etc/redhat-release
Red Hat Enterprise Linux ES release 4 (Nahant Update 5)
root@server # uname -a
Linux server.integrityserver.net... (16 Replies)
Discussion started by: fed.linuxgossip
16 Replies
4. Shell Programming and Scripting
Hi All,
I have directory under /opt/test.
The ownership of the test directory is root:root.
I have login to the server as test user.
I need to have some script to create a directory inside /opt/test.
This script will be called as test user.
When I try to execute... (4 Replies)
Discussion started by: kalpeer
4 Replies
5. Homework & Coursework Questions
first off let me introduce myself. My name is Eric and I am new to linux, I am taking an advanced linux administration class and we are tasked with creating a script to add new users that anyone can run, has to check for the existence of a directory. if the directory does not exist then it has... (12 Replies)
Discussion started by: pbhound
12 Replies
6. UNIX for Dummies Questions & Answers
I've tried to figure this out.
I'm only about 6 mos into my AIX admin duties, but I've got a "security" problem I can't figure out.
I've created a sub directory as follows:
drwx------ 2 root system 256 Apr 13 16:02 mike
I've logged in another session with the following user:
$ id... (2 Replies)
Discussion started by: mpheine
2 Replies
7. Solaris
Hi,
I am new to Solaris and when i am trying to Switch to root login from user, system throws message saying permissions denied...
Steps I Followed:
Created a user and logged into that user by SU username
tried to come back to root but system throws message "permissions denied"
... (7 Replies)
Discussion started by: VijaySolaris
7 Replies
8. UNIX for Advanced & Expert Users
Hi!! one strange problem occurred with my RHEL 5 box.
i'm having logs folder with ownership of non-root user. Created some files with root user under logs folder.
here is the scene:
-rw-r----- 1 root root 1048227 Feb 28 12:34 SystemOut_13.02.28_12.34.10.log
-rw-r----- 1 root root ... (6 Replies)
Discussion started by: sukhdip
6 Replies
9. UNIX for Dummies Questions & Answers
Is there any way to create a file in linux that root user also can't delete? (8 Replies)
Discussion started by: palani13dec
8 Replies
10. UNIX for Dummies Questions & Answers
Hi,
I tired changing password for mqm user in linux server with root user.
But still I couldn't able to login mqm user with changed password.
Can anyone please help on this.
# passwd mqm
Thanks,
Anusha (4 Replies)
Discussion started by: Anusha M
4 Replies
LEARN ABOUT DEBIAN
webcommon.urlencode
WebCommon.urlEncode(3kaya) Kaya module reference WebCommon.urlEncode(3kaya)
NAME
WebCommon::urlEncode - URL encode a string
SYNOPSIS
String urlEncode( String x )
ARGUMENTS
x The string to encode
DESCRIPTION
URL encode a string. You should use this to encode reserved characters in URLs that you wish to be passed literally.
// trying to pass "http://www.example.com" as a parameter
url = "http://localhost/test.cgi?url=";
url += urlEncode("http://www.example.com");
// url = http://localhost/test.cgi?url=http%3A%2F%2Fwww.example.com
Note that in the example above, encoding the whole URL would be incorrect - that would create a relative URL beginning "http://".
AUTHORS
Kaya standard library by Edwin Brady, Chris Morris and others (kaya@kayalang.org). For further information see http://kayalang.org/
LICENSE
The Kaya standard library is free software; you can redistribute it and/or modify it under the terms of the GNU Lesser General Public
License (version 2.1 or any later version) as published by the Free Software Foundation.
RELATED
WebCommon.urlDecode(3kaya)
Kaya October 2012 WebCommon.urlEncode(3kaya)