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Full Discussion: Delete a row from a file if one column containing a date is greater than the current system date
Top Forums UNIX for Dummies Questions & Answers Delete a row from a file if one column containing a date is greater than the current system date Post 302536577 by itkamaraj on Tuesday 5th of July 2011 11:11:45 PM
Old 07-06-2011
Code:
$ today=`date +%Y%m%d`;nawk -F"\~" -v date=$today '{ if( $13 < date) {print $0} }' filename
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~
NETW~US60~000000000013234445~001~~IT~USD~0.33~20090107~99991231~01~01~~

 

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LEARN ABOUT DEBIAN

ubuntu-distro-info

UBUNTU-DISTRO-INFO(1)					      General Commands Manual					     UBUNTU-DISTRO-INFO(1)

NAME

       ubuntu-distro-info - provides information about Ubuntu's distributions

SYNOPSIS

       ubuntu-distro-info [OPTIONS]

OPTIONS

       --date=DATE
	      date for calculating the version (default: today)

       -h, --help
	      display help message and exit

       -a, --all
	      list all known versions

       -d, --devel
	      latest development version

       --lts  latest long term support (LTS) version

       -s, --stable
	      latest stable version

       --supported
	      list of all supported stable versions

       --unsupported
	      list of all unsupported stable versions

       -c, --codename
	      print the codename (default)

       -r, --release
	      print the release version

       -f, --fullname
	      print the full name

SEE ALSO

       debian-distro-info(1), distro-info(1)

AUTHOR

       The script and this manual page was written by Benjamin Drung <bdrung@debian.org>.

distro-info							   January 2011 					     UBUNTU-DISTRO-INFO(1)
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