I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi,
I have a csv file with old data..i need to have only last 30 days from the current dateof data in the file.The fourth field in the file is a date field.i need to write a script to delete the old data by comparing the the fourth field with the (current date -30).I need to delete the rows in... (2 Replies)
Hi, as the title states i need to find a way to search a column for values great than 1000, and if it is, then delete that row.
An example
1 7.021 6.967 116.019 4 U 6.980E+07 0.000E+00 e 0 0 0 0
2 8.292 7.908 118.063 3 U 1.440E+07 0.000E+00 e 0 821 814 ... (3 Replies)
Hi Guys,
Anyone who knows how to compare the current date with the a file containing a date, say for example I have a file that looks like this:
Command was launched from partition 0.
------------------------------------------------
Executing command in server server6
Fri Dec 16... (7 Replies)
I want to delete row in csv file , which row value from 2009-10-01 to 2011-06-03 using script.my csv row data look like:
2009-10-01
2011-03-30
2011-03-31
2011-04-01
2011-06-03
2011-06-30
2011-07-01
2011-09-28 ... (7 Replies)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
Code:
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to write a... (3 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT CENTOS
dm_date
DM_DATE(1) User Contributed Perl Documentation DM_DATE(1)NAME
dm_date - print out the system date and time
SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module.
dm_date [OPTION]... [+FORMAT]
DESCRIPTION
This displays information about the current system time, or some other time. Options are:
-h, --help
Print online help.
-d STRING, --date=STRING
Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date
documentation for details.
-f DATEFILE, --file=DATEFILE
This reads each line in DATEFILE, and extracts a date from it and prints out the information.
Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored.
-r FILE, --reference=FILE
Displays the last modification time of FILE.
-R, --rfc-2822
Displayc the date and time in RFC 2822 format.
Example: Mon, 07 Aug 2006 12:34:56 -0600
-u, --utc, --universal
Converts the date to UT (GMT) and prints out the information.
Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other
is ignored.
The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date.
KNOWN BUGS
None known.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip::Date
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.16.3 2014-06-09 DM_DATE(1)