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Top Forums Shell Programming and Scripting Passing array variable in shell_exec Post 302535865 by fpmurphy on Saturday 2nd of July 2011 09:36:06 AM
Old 07-02-2011
Probably because of incorrect variable scope. See PHP: Variable scope. You are using $aid outside the loop.
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php-config(1)							Scripting Language						     php-config(1)

NAME
php-config - get information about PHP configuration and compile options SYNOPSIS
php-config [options] DESCRIPTION
php-config is a simple shell script for obtaining information about installed PHP configuration. OPTIONS
--prefix Directory prefix where PHP is installed, e.g. /usr/local --includes List of -I options with all include files --ldflags LD Flags which PHP was compiled with --libs Extra libraries which PHP was compiled with --extension-dir Directory where extensions are searched by default --include-dir Directory prefix where header files are installed by default --php-binary Full path to php CLI or CGI binary --php-sapis Show all SAPI modules available --configure-options Configure options to recreate configuration of current PHP installation --version PHP version --vernum PHP version as integer SEE ALSO php(1) VERSION INFORMATION
This manpage describes php, version 5.3.6-13ubuntu3.10. COPYRIGHT
Copyright (C) 1997-2010 The PHP Group This source file is subject to version 3.01 of the PHP license, that is bundled with this package in the file LICENSE, and is available through the world-wide-web at the following url: http://www.php.net/license/3_01.txt If you did not receive a copy of the PHP license and are unable to obtain it through the world-wide-web, please send a note to license@php.net so we can mail you a copy immediately. The PHP Group 2010 php-config(1)
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