hey people..
i have a configuration file that looks like
7080 7988
net04.xxxxx.edu
20
where 20 is the number of threads in the thread pool initially.
net04.xxxxx.edu is the hostname.
and 7080 7988
are two ports. first one for client requests and second one for dns communication. now my... (2 Replies)
Hello,
I have a cat.dat file, i would like shell to read each 3 lines and set this 3 lines to 3 different variables.
my cat.dat is:
11
12
+380486461001
12
13
+380486461002
13
14
+380486461003
i want shell to make a loop and assign 1st line to student_id, 2nd line to... (4 Replies)
The text file has one single row and looks like this
Q1 P1 2006
I have to pick up this values from a shell script into three different variables,
say quarter, period and year from the above text file. Some one know's how to do this? I went through 'sed', dint really know how to... (3 Replies)
Hi,
I have a file like the following...
CUST=
DIR=
NULIST=
name=philps_123
How can i add values to each of these unassigned variables using a shell script?
say for eg: i have values for CUST as onida, dir as /dir/onida, NULIST as /tmp/onida_files. How can i add these values to... (11 Replies)
Hi,
I have a config file that has blank, commented lines. I need to escape commented lines, blank lines, parse the remaining lines and store them in variables or array.
the config file contains the following lines.
# config file
# Define Oracle User
ORA_USER=abcde
ORA_PASS=xyzabc... (8 Replies)
For eg: I have sample.txt file with 4 rows of record like:
user1|password1
user2|password2
user3|password3
user4|password4
The username and password is sepsrated by '|'
I want to get the 1st row value from the file and assign it to two different variables(username and password)
in my... (1 Reply)
I have a file containing multiple values, some of them are pipe separated which are to be read as separate values and some of them are single value all are these need to store in variables.
I need to read this file which is an input to my script
Config.txt
file name, first path, second... (7 Replies)
so i've been used to doing it this way:
SVAL=$(echo "7 3 2 38 3" | awk '{print $2}')
4VAL=$(echo "4:21:N:3" | awk -F":" '{print $4}')
I know there's a way to do it by putting the value in an array and assigning it that way. but i'm not sure how to do it efficiently. any ideas? i dont... (9 Replies)
i have a program that spits out a certain number of values. i dont know the number of values. they can be 4, 10, 7, 20, no idea.
but, i want to be able to assign each of the value returned by this program to a variable.
in the latest instance, the program gave the following 6 values:
4... (8 Replies)
The file1 contains mistakes and looks like
1 No one have never become rich by giving.
Anne Dickens
2 No one is worthless in this globe who lightens the weights of other.
Charles_Dickens
file2 contains the correction of words and looks like
rich poor
have has
never ever... (3 Replies)
Discussion started by: sammy777888
3 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)