In bash script, how to assign output of a command to a variable while keeping tabs?
Hi, wondering if it's been asked before but didn't find matches from google. Basically I have this line:
Now somehow the '\t' from the echo output gets replaced with white space and then stored in $myvar.
It creates a problem for me later to use tab as delimiter to do cut on $myvar. Anyway to keep the tabs?
Last edited by Franklin52; 06-28-2011 at 03:41 AM..
Reason: Please use code tags for code and data samples, thank you
Hi,
I am giving a grep command, and i am getting the output. i want to store it in a variable
for eg
a = grep '12345' /dir/1/2/log.txt ( the output is number)
b= grep 'basic' /dir/1/2/log1.txt (in this case the output is character)
so how to assign the output of grep to a variable
... (1 Reply)
Hi Guys !
I am new to unix and want to find out how we can make sql statement data to shell script variable?
Any help/suggestion is greatly appreciated
-Chandra (1 Reply)
Hi
I am trying to write a function that needs to be able to assign the last run shell command to a variable. The actual command string itself not the exit code of the command.
I am using the bash command recall ability to do this as follows:
alias pb='ps | grep ash' ... (3 Replies)
Hi Friends...
Please assist me to assign the result of a SQL query that results two column, to two variables.
Pls find the below code that I write for assigning one column to one variable. and please correct if anything wrong..
#! /bin/sh
no='
sqlplus -s uname/password@DBname... (4 Replies)
Hi,
I work in ksh88.
I have an interective script which prompts the user for the input and returns numeric value depending on the input provided. I need to call this script inside another script and then assign the resulting output the the variable.
The call like that A=`my script` obviously... (6 Replies)
Hi ,
I would like to assign command (with pipe) output to a variable. The code is as follows. The goal of the code is to get the last folder folder with a particular name pattern.
myDate=`ls | grep 2009 | tail -1`
echo "myDate=" $myDate
However, in the presence of the pipe, the code... (3 Replies)
greetings all,
I am have a heck of a time trying to accomplish a very simple thing. I have an array of "shortname<spaces>id" created from a dscl output. I want to assign shortname=word1 and id=word2. I have tried
shortname=$(${textArray} | awk '{print $1}') - and get 'awk : cannot open... (3 Replies)
Code
set -x
STATUS="0"
echo $STATUS
for i in `ls -ltr Report*|awk '{ print $9 }'`
do
if
then
flg = "`head -1 "$i" |cut -c 31-33`"
echo `head -1 "$i" |cut -c 31-33`
echo $flg
if
then
echo "having Fun"
STATUS="2"
else
echo "no Fun"
fi
fi (2 Replies)
In the else of the main if condition .
else
set lnk = $(readlink -f <path> | cut -d '/' -f7)
echo "$lnk"
if ]
When I run the above on command line , the execution seems to be fine and I get the desired output. But when I try to assign it to a variable within a loop... (12 Replies)
Discussion started by: sankasu
12 Replies
LEARN ABOUT CENTOS
symbol
Symbol(3pm) Perl Programmers Reference Guide Symbol(3pm)NAME
Symbol - manipulate Perl symbols and their names
SYNOPSIS
use Symbol;
$sym = gensym;
open($sym, "filename");
$_ = <$sym>;
# etc.
ungensym $sym; # no effect
# replace *FOO{IO} handle but not $FOO, %FOO, etc.
*FOO = geniosym;
print qualify("x"), "
"; # "main::x"
print qualify("x", "FOO"), "
"; # "FOO::x"
print qualify("BAR::x"), "
"; # "BAR::x"
print qualify("BAR::x", "FOO"), "
"; # "BAR::x"
print qualify("STDOUT", "FOO"), "
"; # "main::STDOUT" (global)
print qualify(*x), "
"; # returns *x
print qualify(*x, "FOO"), "
"; # returns *x
use strict refs;
print { qualify_to_ref $fh } "foo!
";
$ref = qualify_to_ref $name, $pkg;
use Symbol qw(delete_package);
delete_package('Foo::Bar');
print "deleted
" unless exists $Foo::{'Bar::'};
DESCRIPTION
"Symbol::gensym" creates an anonymous glob and returns a reference to it. Such a glob reference can be used as a file or directory handle.
For backward compatibility with older implementations that didn't support anonymous globs, "Symbol::ungensym" is also provided. But it
doesn't do anything.
"Symbol::geniosym" creates an anonymous IO handle. This can be assigned into an existing glob without affecting the non-IO portions of the
glob.
"Symbol::qualify" turns unqualified symbol names into qualified variable names (e.g. "myvar" -> "MyPackage::myvar"). If it is given a
second parameter, "qualify" uses it as the default package; otherwise, it uses the package of its caller. Regardless, global variable
names (e.g. "STDOUT", "ENV", "SIG") are always qualified with "main::".
Qualification applies only to symbol names (strings). References are left unchanged under the assumption that they are glob references,
which are qualified by their nature.
"Symbol::qualify_to_ref" is just like "Symbol::qualify" except that it returns a glob ref rather than a symbol name, so you can use the
result even if "use strict 'refs'" is in effect.
"Symbol::delete_package" wipes out a whole package namespace. Note this routine is not exported by default--you may want to import it
explicitly.
BUGS
"Symbol::delete_package" is a bit too powerful. It undefines every symbol that lives in the specified package. Since perl, for performance
reasons, does not perform a symbol table lookup each time a function is called or a global variable is accessed, some code that has already
been loaded and that makes use of symbols in package "Foo" may stop working after you delete "Foo", even if you reload the "Foo" module
afterwards.
perl v5.16.3 2013-02-26 Symbol(3pm)