sed pattern to delete lines containing a pattern, except the first occurance Post: 302533349

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[sed] Finding and sticking the pattern to the beginning of successive lines up to the next pattern

I have a file like below. 2018.07.01, Sunday 09:27 some text 123456789 0 21 0.06 0.07 0.00 2018.07.02, Monday 09:31 some text 123456789 1 41 0.26 0.32 0.00 09:39 some text 456789012 1 0.07 0.09 0.09 09:45 some text 932469494 1 55 0.29 0.36 0.00 16:49 some text 123456789 0 48 0.12 0.15 0.00...

LEARN ABOUT MINIX

grep

GREP(1) 						      General Commands Manual							   GREP(1)

NAME

       grep - search a file for lines containing a given pattern

SYNOPSIS

       grep [-elnsv] pattern [file] ...

OPTIONS

       -e     -e pattern is the same as pattern

       -c     Print a count of lines matched

       -i     Ignore case

       -l     Print file names, no lines

       -n     Print line numbers

       -s     Status only, no printed output

       -v     Select lines that do not match

EXAMPLES

       grep mouse file	   # Find lines in file containing mouse

       grep [0-9] file	   # Print lines containing a digit

DESCRIPTION

       Grep  searches  one  or	more  files (by default, stdin) and selects out all the lines that match the pattern.  All the regular expressions
       accepted by ed and mined are allowed.  In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or  1
       occurrences,  and  |  can  be used between two regular expressions to mean either one of them.  Parentheses can be used for grouping.  If a
       match is found, exit status 0 is returned.  If no match is found, exit status 1 is returned.  If an error is detected,  exit  status  2	is
       returned.

SEE ALSO

       cgrep(1), fgrep(1), sed(1), awk(9).

																	   GREP(1)

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copy, then delete lines in file with sed using a pattern

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