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Top Forums Shell Programming and Scripting find command with wildcard directory Post 302533074 by Corona688 on Wednesday 22nd of June 2011 05:00:23 PM
Old 06-22-2011
Quote:
Originally Posted by srini0603
can you tell me a bit more about two finds?
I think I forgot a pipe. No wonder it was puzzling you.

Code:
# Find and print all directories in .../PROD-* beginning with [0-9a-f]
find /Production/ST/st*/Outbound/Prod/PROD-* -type d -name '[0-9a-f]*' -print -name '*' -prune |
# Read lines like /Production/ST/.../bcfa0dbbcf17f28c768d1d34da6b48a4 into DIR, one-by-one
while read DIR
do
        # We feed that whole directory into another find, telling it to look
        # for files.  It prints them one by one, piped into xargs,
        # which uses them as arguments for rm.
        find "${DIR}/PGP" -type f -mtime +2 | xargs -d '\n' echo rm
 
        # Remove these directories only if they're empty
        rmdir "${DIR}/PGP" && rmdir "${DIR}"
# the rmdir's will cause some error messages when they fail, redirect that to /dev/null
done 2> /dev/null

If that didn't answer your question you'll need to ask about something specific.
Quote:
so in my case do I have to give it as 0-9,a-z as it could be anything between 0-9 and a-z as the first letter of the folder.
I don't think so, those look like hex: binary numbers encoded as ASCII digits 0-9 and a-f.
Quote:
is there any restriction on the # of directories I can search using this wildcard?
There's no limit on find -name '*', no, because it can process them one-by-one. When you expand * inside the shell itself, it has to find all of them at once, before find is even run, potentially running out of room.
Quote:
also won't the rmdir "${DIR}" delete the full structure? I just need only till the 32 char folder deleted and the rest should be intact.
"rmdir /path/to/folder" only removes 'folder'. And it won't even do that unless it's empty. So I try to remove /Production/ST/st*/Outbound/Prod/PROD-*/bcfa0dbbcf17f28c768d1d34da6b48a4/PGP, and if that succeeds, I try to remove /Production/ST/st*/Outbound/Prod/PROD-*/bcfa0dbbcf17f28c768d1d34da6b48a4 itself.

And as I said, don't remove the echo until you're sure it does what you want.
 

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lndir(1X)																 lndir(1X)

NAME
lndir - create a shadow directory of symbolic links to another directory tree SYNOPSIS
lndir fromdir [todir] DESCRIPTION
lndir makes a shadow copy todir of a directory tree fromdir, except that the shadow is not populated with real files but instead with sym- bolic links pointing at the real files in the fromdir directory tree. This is usually useful for maintaining source code for different machine architectures. You create a shadow directory containing links to the real source which you will have usually NFS mounted from a machine of a different architecture, and then recompile it. The object files will be in the shadow directory, while the source files in the shadow directory are just symlinks to the real files. This has the advantage that if you update the source, you need not propagate the change to the other architectures by hand, since all source in shadow directories are symlinks to the real thing: just cd to the shadow directory and recompile. The todir argument is optional and defaults to the current directory. The fromdir argument may be relative (e.g., ../src) and is relative to todir (not the current directory). Note that RCS, SCCS, and CVS.adm directories are not shadowed. Note also that if you add files, you must run lndir again. Deleting files is difficult because the symlinks will point to places that no longer exist. BUGS
The patch routine needs to be able to change the files. You should never run patch from a shadow directory. Use a command like the following to clear out all files before you can relink (if the fromdir has been moved, for instance): find todir -type l -print | xargs rm The following command will find all files that are not directories: find . ! -type d -print lndir(1X)
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